How to convert and Integer to an 64-bit byte representation in python

Question

I am trying to convert an integer. E.g 3063294273, to a 64-bit big endian encoded byte representation. So for example if I have a value = 1 my output should be
0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x01

What would be the best approach to do this in python?

Edit: I saw the other question provided in Convert a Python int into a big-endian string of bytes. But in the other question, the author was not asking for a specific size of the output. Which is important for my problem.

Your example shows 128 bits (16 instances of 8-bit (two hex digit)) values. — Tom Karzes, Jun 08 '19 at 10:37
Possible duplicate of [Convert a Python int into a big-endian string of bytes](https://stackoverflow.com/questions/846038/convert-a-python-int-into-a-big-endian-string-of-bytes) — Arkistarvh Kltzuonstev, Jun 08 '19 at 10:38
I dont see the duplicate? In the provided other question, the author was not asking for a specific size of the output. — JustPlayin, Jun 08 '19 at 11:54

score 1 · Accepted Answer · answered Jun 08 '19 at 10:36

1

int.to_bytes

>>> value = 1
>>> value.to_bytes(8, 'big')
b'\x00\x00\x00\x00\x00\x00\x00\x01'

(Your sample output is 128 bits, so if you meant that, use 16.)

answered Jun 08 '19 at 10:36

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How to convert and Integer to an 64-bit byte representation in python

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