Increment the month in python and then print the name of the incremented month

Question

Is there any way to print the name of the incremented month?

import datetime
currentDT = datetime.datetime.now()
currentmonth=currentDT.strftime("%B")
nextmonth = datetime.date.today().month + 1

Here I get the "nextmonth" in form of integer.

But how can I get the name of that month i.e. July. I even tried using this,

next_month=nextmonth.strftime("%B")

But it returned the error,

AttributeError: 'int' object has no attribute 'strftime'

Possible duplicate of [Get month name from number](https://stackoverflow.com/questions/6557553/get-month-name-from-number) — DSC, Jun 08 '19 at 16:04
You know how to get the index of the next month. From there you can use the link. — DSC, Jun 08 '19 at 16:08

score 1 · Answer 1 · edited Jun 08 '19 at 16:44

1

You can use calendar module

import calendar
print (calendar.month_name[4])

It is built-in.

edited Jun 08 '19 at 16:44

Azat Ibrakov

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answered Jun 08 '19 at 16:08

Sakib Farhad

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OP already imports datetime so why not use datetime functionality? – DSC Jun 08 '19 at 16:09
Would be a better approach, using `datetime` – Sakib Farhad Jun 08 '19 at 16:11
1

The `calendar` module is definitely the correct approach, regardless of how many times the user has imported datetime (or any other modules). – thebjorn Jun 08 '19 at 16:17

Smart Manoj · Answer 2 · 2019-06-08T17:07:15.960

0

For edge cases like December as calendar.month_name has 13 elements

import calendar
import datetime
months=calendar.month_name[1:]
a=months[datetime.date.today().month % 12]
print(a)

edited Jun 08 '19 at 17:07

answered Jun 08 '19 at 16:23

Smart Manoj

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Azat Ibrakov · Answer 3 · 2019-06-08T16:39:59.403

-1

Your problem is that nextmonth is an int representing month number, not date object, so you can use calendar.month_name array like

>>> import calendar
>>> calendar.month_name[(datetime.date.today().month + 1) % 12]
'July'

edited Jun 08 '19 at 16:39

answered Jun 08 '19 at 16:08

Azat Ibrakov

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Fails for December – Smart Manoj Jun 08 '19 at 17:01

score -2 · Answer 4 · edited Jul 03 '19 at 06:41

-2

You can do it like this in python 3

import time,datetime

currentDT = datetime.datetime.now()
currentmonth=currentDT.strftime("%B")
nextmonth = datetime.date.today().month + 1
print(time.strftime('%B', time.struct_time((0, nextmonth, 0,)+(0,)*6)))

edited Jul 03 '19 at 06:41

piet.t

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answered Jun 08 '19 at 16:07

Rajan Sharma

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Your code at `print(time.strftime('%B', time.struct_time((0, nextmonth, 0,)+(0,)*6)))` raise an exception: `Exception has occurred: ValueError strftime() requires year in [1; 9999]`. Do you mean: `print(time.strftime('%B', time.struct_time((1, nextmonth, 0,)+(0,)*6)))` ? – Carlo Zanocco Sep 28 '20 at 16:35

Increment the month in python and then print the name of the incremented month

4 Answers4