list comphrension on nested distionary

Question

I have a python dict like so:

tt={'plot1':[
      {'var': 'ok__you', 'uuid': '98782098109'},
      {'var': 'hdg__akj', 'uuid': '712837901'}
      ], 
    'plot2': [
      {'var': 'ok__you2', 'uuid': '987820981092'},
      {'var': 'hdg__akj2', 'uuid': '7128379012'}
    ]}

I am trying to get all the uuids into one single list, so, I do:

lst=[v_i['uuid'] for v_i in value for key,value in tt.items()]

and I get thrown:

NameError: name 'value' is not defined

I have no clue why this is - I have specified the value in the tt.items() iteration - not sure why this error is being thrown?

Would apreciate any tips!

`lst = [k['uuid'] for k in tt for k in tt[k]]` – tonypdmtr Jun 08 '19 at 23:10 — tonypdmtr, Jun 08 '19 at 23:10

score 2 · Answer 1 · answered Jun 08 '19 at 22:26

2

You swapped the order of the two for loops

lst=[v_i['uuid'] for key,value in tt.items() for v_i in value]

The output will then be

['98782098109', '712837901', '987820981092', '7128379012']

Also since you are not using the key, you could just iterate on the values of the dictionaries

lst=[v_i['uuid'] for value in tt.values() for v_i in value]

answered Jun 08 '19 at 22:26

Devesh Kumar Singh

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Thanks Davesh - probably because I am working a bit late today :) – JohnJ Jun 08 '19 at 22:28
No worries @JohnJ :) It happens to the best of us, if the answer helped you, please consider marking it as accepted :) – Devesh Kumar Singh Jun 08 '19 at 22:32

list comphrension on nested distionary

1 Answers1