How could I get a dict having max value for a key in a list containing multiple dict?

Question

I have this list

result = [{"name": "A", "score": 35, "other_details": ""},
          {"name": "A", "score": 60,"other_details": ""},
          {"name": "B", "score": 45, "other_details": ""}, 
          {"name": "B", "score": 34, "other_details": ""},
          {"name":"C", "score": 65, "other_details": ""}]

Now, I want to get the whole dictionary on the basis of maximum score for each name.

My expected output is:

[{"name": "A", "score": 60,"other_details": ""}]

[{"name": "B", "score": 45, "other_details": ""}]

[{"name":"C", "score": 65, "other_details": ""}]

Possible duplicate of [How do I sort a list of dictionaries by a value of the dictionary?](https://stackoverflow.com/questions/72899/how-do-i-sort-a-list-of-dictionaries-by-a-value-of-the-dictionary) — ggorlen, Jun 10 '19 at 04:31

score 0 · Accepted Answer · answered Jun 10 '19 at 05:23

Using itertools.groupby

Ex:

from itertools import groupby

result = [{"name": "A", "score": 35, "other_details": ""},
          {"name": "A", "score": 60,"other_details": ""},
          {"name": "B", "score": 45, "other_details": ""}, 
          {"name": "B", "score": 34, "other_details": ""},
          {"name":"C", "score": 65, "other_details": ""}]

data_result = [max(list(v), key=lambda x: x["score"]) for k, v in groupby(sorted(result, key=lambda x: x["name"]), lambda x: x["name"])]
print(data_result)

Output:

[{'name': 'A', 'other_details': '', 'score': 60},
 {'name': 'B', 'other_details': '', 'score': 45},
 {'name': 'C', 'other_details': '', 'score': 65}]

How could I get a dict having max value for a key in a list containing multiple dict?

1 Answers1