A random list of four items, but with no duplicates

Question

I want to create a random list, but none of the numbers in the list can have the same value. and only numbers from 0 to 9

I have tried random.randint, random.choice, random.randrage, even tried: random.randint(0 > value < 9)

number = [random.randint(0,9),random.randint(0,9),random.randint(0,9),random.randint(0,9)]

for index,value in enumerate(number):
    values = [0,1,2,3,4,5,6,7,8,9]
    values.remove(value)
    if value == number[index-1] or number[index-2] or number[index-3]:
        number[index] = random.choice(values)


print(number)

i want to get a list of four numbers which are not duplicates, but i keep on getting duplicates?

`random.sample(range(10), 4)`? – jonrsharpe Jun 10 '19 at 19:27 — jonrsharpe, Jun 10 '19 at 19:27

score 0 · Answer 1 · answered Jun 10 '19 at 19:36

You are looking for random.sample:

>>> random.sample(range(0,10), 4)
[9, 6, 2, 0]

The values are chosen without replacement, so there are no duplicates in output list. Because of this, a request for a sample larger than the input sequence will raise a ValueError instead.

score 0 · Accepted Answer · answered Jun 10 '19 at 19:37

0

from random import sample

my_list = sample(range(10),4)

print(my_list)

Replace range(10) with whatever list you want to grab a random sample from in the future.

answered Jun 10 '19 at 19:37

S Hanson

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Bruh, if I knew the answer was that easy, I wouldnt have gone through the long process of writing all that code... but thanks for the answer – Vilmer Jun 10 '19 at 19:40

A random list of four items, but with no duplicates

2 Answers2