How to make a list out of a set of result?

Question

So here I defined a function in python that tells if a given number is even or odd.

Now i want to create a list with the numbers in the result as its elemets, how is that possible?

def even_till_n(number):
     for in range(number+1): 
        if  (i%2 == 0):
             print(i)

Possible duplicate of [Python- How to generate new list from variable in a loop?](https://stackoverflow.com/questions/16888880/python-how-to-generate-new-list-from-variable-in-a-loop) — juanpa.arrivillaga, Jun 11 '19 at 17:11
Also, please use the generic [python] tag for all python questions, use a version specific tag at your discretion — juanpa.arrivillaga, Jun 11 '19 at 17:11

score 1 · Answer 1 · answered Jun 11 '19 at 17:23

You need to create a list variable and append values to it. Then make your function return that list:

def even_till_n(number):
     result = list()
     for i in range(number+1): 
        if  (i%2 == 0):
             result.append(i)
     return result

# usage ...

test = even_till_n(10)
print(test)

# [0, 2, 4, 6, 8, 10]

score 0 · Answer 2 · answered Jun 11 '19 at 16:57

0

Use a list-comprehension.

def even_till_n(number):
    return [x for x in range(number+1) if x%2 == 0]

answered Jun 11 '19 at 16:57

rdas

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List-comprehensions are a feature of python: https://www.pythonforbeginners.com/basics/list-comprehensions-in-python they follow are used to create lists from other iterables – rdas Jun 11 '19 at 17:02
1

If the OP doesn't even understand how construct a list, perhaps throwing a list comprehension at them isn't very helpful pedagogically. – juanpa.arrivillaga Jun 11 '19 at 17:10

How to make a list out of a set of result?

2 Answers2