Xlsx2csv python implementation:
Could only execute Xlsx2csv with sheetid parameter. In order to get sheet names and ids, get_sheet_details was used.
csvfrmxlsx creates csv files for each sheet in csv folder under parent directory.
import pandas as pd
from pathlib import Path
def get_sheet_details(filename):
import os
import xmltodict
import shutil
import zipfile
sheets = []
# Make a temporary directory with the file name
directory_to_extract_to = (filename.with_suffix(''))
os.mkdir(directory_to_extract_to)
# Extract the xlsx file as it is just a zip file
zip_ref = zipfile.ZipFile(filename, 'r')
zip_ref.extractall(directory_to_extract_to)
zip_ref.close()
# Open the workbook.xml which is very light and only has meta data, get sheets from it
path_to_workbook = directory_to_extract_to / 'xl' / 'workbook.xml'
with open(path_to_workbook, 'r') as f:
xml = f.read()
dictionary = xmltodict.parse(xml)
for sheet in dictionary['workbook']['sheets']['sheet']:
sheet_details = {
'id': sheet['@sheetId'], # can be sheetId for some versions
'name': sheet['@name'] # can be name
}
sheets.append(sheet_details)
# Delete the extracted files directory
shutil.rmtree(directory_to_extract_to)
return sheets
def csvfrmxlsx(xlsxfl, df): # create csv files in csv folder on parent directory
from xlsx2csv import Xlsx2csv
for index, row in df.iterrows():
shnum = row['id']
shnph = xlsxfl.parent / 'csv' / Path(row['name'] + '.csv') # path for converted csv file
Xlsx2csv(str(xlsxfl), outputencoding="utf-8").convert(str(shnph), sheetid=int(shnum))
return
pthfnc = 'c:/xlsx/'
wrkfl = 'my.xlsx'
xls_file = Path(pthfnc + wrkfl)
sheetsdic = get_sheet_details(xls_file) # dictionary with sheet names and ids without opening xlsx file
df = pd.DataFrame.from_dict(sheetsdic)
csvfrmxlsx(xls_file, df) # df with sheets to be converted