Skipping int 0 skips False too

Question

I got list of integers and keywords and i'm trying to remove only zeros from list with for loop - continue, but keyword False removes too, and how to prevent removing False ? ? ?

a = [1,2,0,1,0,1,None,0,False]

for x in a:
    if x ==0:
        continue

A better approach is `type(x) is int` or `x == 0 and x is not False` — qwr, Jun 12 '19 at 15:53
^ no, a better approach would be `not (isinstance(x, int) and x == 0)` — cs95, Jun 12 '19 at 15:55
`str(x)` is atrocious (false positive on the string `'0'`, for starters). `type(x) is int` works, but only if you do not expect floats (0.0 will not be matched) or subclasses of int. The `isinstance` way fails because `isinstance(False, int)` is `True` (booleans are a subclass of integers). In short: go see the duplicate, where the accepted answer is fine. — Leporello, Jun 12 '19 at 15:59

score 0 · Accepted Answer · answered Jun 12 '19 at 15:55

0

To compare to exactly 0 use the is keyword:

a = [1,2,0,1,0,1,None,0,False]

for x in a: 
    if x is 0:
        continue
    print(x)

answered Jun 12 '19 at 15:55

Jab

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-1 because although in works in that exact case (on the standard Python implementation), it will fail with no apparent reason when the value to compare to is a different integer or a float. See https://stackoverflow.com/questions/306313/is-operator-behaves-unexpectedly-with-integers – Leporello Jun 12 '19 at 16:02
Thank you it works good, Suddenly i could not think about keyword is to use, – Xocho Jun 12 '19 at 17:38

Skipping int 0 skips False too

1 Answers1