How to separate with commas an unpacked list of tuples

Question

Unpacking the resulting list of tuples into a comma-separated values.

Using FuzzyWuzzy, I am comparing 2 files and want to output the results into a 3rd file.

Building out from this SO question: Python: Keepning only the outerloop max result when comparing string similarity of two lists

The output is:

[('Item_number', ('Item number', 91)), ('Item', ('Item name', 62))]

Using this unpack method,I was able to separate the values:

for i in mapper:
    print(*[i[0]],*[*i[1]])

Output:

Item_number Item number 91
Item Item name 62

Now, here is where I fall short. I am looking for the individual values to be comma-separated in order to be saved to a CSV file.

I tested many other solutions such as itertools but without success such as:

[('I', 't', 'e', 'm', '_', 'n', 'u', 'm', 'b', 'e', 'r', 'Item number', 91), ('I', 't', 'e', 'm', 'Item name', 62)]

Expected output:

Item_number, Item number, 91
Item, Item name, 62

Note: I am not looking for itertool specific solution but rather a solution that make sense.

Thanks for your interest.

Can you please rephrase the question? Minimal, working example and knowledege, what you got and you expected would help. — Radosław Cybulski, Jun 13 '19 at 14:30

score 2 · Accepted Answer · answered Jun 13 '19 at 14:32

2

try unpacking it to the individual components, then printing them with commas in between:

for (i,(j,k)) in mapper:
    print(i,j,k, sep=',')

(would probably be better to give i, j, and k meaningful names, based on what the values actaully are...)

answered Jun 13 '19 at 14:32

Adam.Er8

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score 1 · Answer 2 · answered Jun 13 '19 at 14:30

You could use a list comprehension, extending the values from the second tuples using extended iterable unpacking, and then write the list to csv (check this post on how to create a csv file from a list):

l = [('Item_number', ('Item number', 91)), ('Item', ('Item name', 62))]

[[i, *j] for i, j in l]
# [['Item_number', 'Item number', 91], ['Item', 'Item name', 62]]

LiuXiMin · Answer 3 · 2019-06-13T15:52:53.797

0

Based on your existing code, you can use such a solution:

mapper = [('Item_number', ('Item number', 91)), ('Item', ('Item name', 62))]
for i in mapper:
    print(', '.join(map(str, (*[i[0]],*[*i[1]]))))
Item_number, Item number, 91
Item, Item name, 62

edited Jun 13 '19 at 15:52

answered Jun 13 '19 at 14:55

LiuXiMin

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I learn from you the proper syntax for using ', '.join(map(str())) in that specific case. Most certainly, this will be handy moving forward. Thx – Frederic Gilbert Jun 13 '19 at 15:30

How to separate with commas an unpacked list of tuples

3 Answers3