Python Current Folder of Script

Question

I'm trying to return the current folder path of a python script, here is what I have

#test.py
import os
THIS_FOLDER = os.path.dirname(os.path.abspath('__file__'))
print(THIS_FOLDER)

When I run this script, it returns the folder that I am in when running it in the command prompt, not the folder of the python script.. How can I return the folder of the current python file?

user@vm:~$ python -u dir/test.py
/home/user

user@vm:~$ cd dir
user@vm:~/dir$ python -u test.py
/home/user/dir

@user66081 actually, it works in python on linux, but not in my jupyter notebook in windows.. `NameError: name '__file__' is not defined` — Adam12344, Jun 13 '19 at 16:12
@Adam12344 `abspath` takes string and assumes it's a relative path, usually with a filename at the end which is unchanged — micke, Jun 13 '19 at 16:17

micke · Answer 1 · 2019-06-13T16:58:53.840

0

You need to remove the quotes around __file__

In your script os.path.abspath gets a string '__file__' and returns '/home/user/__file__' (same as ./__file__ on *nix).

os.path.dirname then just strips the filename at the end of the string so your working directory (./) is left.

Edit: You want the absolute path of the folder that contains the script (__file__)
That becomes: os.path.abspath(os.path.dirname(__file__))

Check out this answer for more information.

edited Jun 13 '19 at 16:58

answered Jun 13 '19 at 16:21

micke

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Is there a way to get this to work in Jupyter Notebooks? Removing the quotes makes it work when running the file in linux – Adam12344 Jun 13 '19 at 16:31
@Adam12344 I updated the answer and linked a similar answer for you. – micke Jun 13 '19 at 16:59

Python Current Folder of Script

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