Creating A Template Wrapper for std::bind

Question

I am trying to create a simple wrapper function for std::bind, which will take a member function.

template<typename T, typename F>
void myBindFunction(T &t)
{
   std::bind(T::F, t );
}

MyClass a = MyClass();
myBindFunction <MyClass, &MyClass::m_Function>( a );

I'm not sure if what I am trying to achieve it possible?

Why would you need that? Why using `std::bind` at all, a lambda function would be more appropriate IMO. — πάντα ῥεῖ, Jun 16 '19 at 13:09
You might want to look at this: https://stackoverflow.com/questions/37636373/how-stdbind-works-with-member-functions . Regardless, usually using lambdas is a better and more readable alternative — CuriouslyRecurringThoughts, Jun 16 '19 at 13:12

songyuanyao · Accepted Answer · 2019-06-16T14:08:28.267

1

You can make the 2nd template parameter a non-type template parameter, i.e. a member function pointer.

template<typename T, void(T::*F)()>
void myBindFunction(T &t)
{
   std::bind(F, t); // bind the member function pointer with the object t
}

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edited Jun 16 '19 at 14:08

answered Jun 16 '19 at 13:15

songyuanyao

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Creating A Template Wrapper for std::bind

1 Answers1