How do I convert `str` object to `datetime` object in python

Question

I have a string in this format: 2019-06-18T11:00:10.499378622Z. I am trying to convert this into a datetime object.

I have tried

s_datetime = datetime.strptime(s_datetime_string, '%Y-%m-%d*%H:%M:%S*')

import datetime.datetime
s_datetime = datetime.strptime(s_datetime_string, '%Y-%m-%d*%H:%M:%S*')

Getting ValueError as the regex does not match

Highly recommend the arrow package as a replacement for datetime. — WombatPM, Jun 19 '19 at 02:50

Robert Kearns · Accepted Answer · 2019-07-15T09:37:01.860

I also get this error, so I made a little function to use whenever I deal with ISO times.

def ISOtstr(iso):

    dcomponents = [1,1,1]
    dcomponents[0] = iso[:4]
    dcomponents[1] = iso[5:7]
    dcomponents[2] = iso[8:10]
    tcomponents = [1,1,1]
    tcomponents[0] = iso[11:13]
    tcomponents[1] = iso[14:16]
    tcomponents[2] = iso[17:19]
    d = dcomponents
    t = tcomponents
    string = "{}-{}-{} {}:{}:{}".format(d[0],d[1],d[2],t[0],t[1],t[2])
    return string

Convert your ISO to a string:

string = '2019-06-18T11:00:10.499378622Z'
date_string = ISOtstring(string)
date_obj = datetime.datetime.strptime(date_string, '%Y-%m-%d %H:%M:%S')
#Output
#datetime.datetime(2019, 6, 18, 11, 0, 10)

There is most likely a better way to do it. But I use this whenever dealing with ISO strings.

If your using it frequently you could make this a separate function:

def ISOtdatetime(iso):
  date_string = ISOtstring(iso)
  date_obj = datetime.datetime.strptime(date_string, '%Y-%m-%d %H:%M:%S')
  return date_obj

Just realized I had some meaningless code in there from when I first created the function. They have been removed.

thanks a lot, you saved my day @jedkea! – DevBabai Jun 19 '19 at 03:05 — DevBabai, Jun 19 '19 at 03:05

score 0 · Answer 2 · answered Jun 19 '19 at 02:02

0

I also got an error with your input especially on the unit of second. But when I changed your unit of second a little bit, it works. So, I have no idea about this.

from datetime import datetime

s_datetime = datetime.strptime('2019-06-18T11:00:10.499378Z', '%Y-%m-%dT%H:%M:%S.%fZ')
print(s_datetime)
print(type(s_datetime))

Output:

2019-06-18 11:00:10.499378
<class 'datetime.datetime'>

answered Jun 19 '19 at 02:02

YusufUMS

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I am still having trouble with it :/ `ValueError: time data '2019-06-18T15:08:46.131737185Z' does not match format '%Y-%m-%dT%H:%M:%S.%fZ' – DevBabai Jun 19 '19 at 03:04

How do I convert `str` object to `datetime` object in python

2 Answers2