In python (3x version)
'\' # this is error no doubt
'\\' # this prints two backslashes ,i.e., '\\'
r'\' # this also gives error
'anytext \ anytext' # gives 'anytext \\ anytext'
r and R tried both but didn't work
tried to escape the escape character \ ,i.e., '\\' but didn't work enter image description here
In IDLE (Python's Integrated Development and Learning Environment), expression values have their representation echoed to stdout.
As https://docs.python.org/3/library/idle.html explains:
The
reprfunction is used for interactive echo of expression values. It returns an altered version of the input string in which control codes, some BMP codepoints, and all non-BMP codepoints are replaced with escape codes.
If you want to print a string, use the print() function. Otherwise you'll get its representation.
Consider the following code entered into IDLE:
>>> hitman_str = "Agent \ 47"
>>> print(hitman_str) # We see only one slash when using print
Agent \ 47
>>> hitman_str # This shows the representation, which shows two slashes
'Agent \\ 47'
>>> print(repr(hitman_str)) # Same as above
'Agent \\ 47'
There are multiple ways to get a string with only one slash:
single_slash1 = "\\"
>>> print(single_slash1)
\
>>> single_slash2 = "\ "[0]
>>> print(single_slash2)
\
>>> single_slash1 == single_slash2
True
Similarly, there are multiple ways to get a string with two consecutive slashes:
>>> two_slashes1 = "\\\\"
>>> print(two_slashes1)
\\
>>> print(repr(two_slashes1))
'\\\\'
>>> two_slashes1
'\\\\'
>>> len(two_slashes1)
2
>>> two_slashes2 = r"\\"
>>> print(two_slashes2)
\\
>>> print(repr(two_slashes2))
'\\\\'
>>> two_slashes2
'\\\\'
>>> len(two_slashes2)
2
We can confirm hitman_str only has one slash:
>>> hitman_str.count(single_slash1)
1
We can iterate through the string and print each character and its Unicode code point. As expected, this shows only one slash:
>>> for char in hitman_str:
print(char, ord(char))
A 65
g 103
e 101
n 110
t 116
32
\ 92
32
4 52
7 55
Raw strings are very handy, especially for Windows paths if you don't wanna use os.path or pathlib:
>>> filename = r"C:\Users\Lee Hong\Documents\New Letters\Impatient 1999-06-14.txt" # Works fine
>>> filename = "C:\Users\Lee Hong\Documents\New Letters\Impatient 1999-06-14.txt" # Error
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
>>> raw_str = r"This \\\has \11 \\slashes \\and \no \line \break"
>>> print(raw_str)
This \\\has \11 \\slashes \\and \no \line \break
>>> raw_str.count(single_slash1)
11
For more information, including a list of escape sequences to watch out for, refer to https://docs.python.org/3/reference/lexical_analysis.html#string-and-bytes-literals
If I am understanding your questions correctly, like this: print("\\")?
