Ignoring a string within a token regex

Question

Im trying to parse a log file and having a hard time trying to ignore a string within a token.

Part of the log I'm trying to parse:

[Wed Mar 06 20:56:27.121877 2019]

I want to create a token for the date where it should ignore any value after the second till the year and look like this:

Mar 06 20:56:27 2019

My regex string looks something like this at moment:

\[\S+ (\S+ \d+ \d+:\d+:\d+)

Can you give complete code how you are using this regex against this entry? — Aakash, Jun 21 '19 at 08:00
Hi Aakash unfortunately i cannot share the the log file. However [Wed Mar 06 20:56:27.121877 2019] is at the beginning of the line in each log. — Gaurav Bhatnagar, Jun 21 '19 at 08:17

score 0 · Answer 1 · answered Jun 21 '19 at 08:12

0

You could do something like this:

public class MyClass {
  public static void main(String args[]) {
    String test = "[Wed Mar 06 20:56:27.121877 2019]";
    String[] arr = test.split(" ");
    System.out.println(arr[1]+" "+arr[2]+" "+arr[3].substring(0,8)+" "+arr[4].substring(0,4));
  }
}

Output:

Mar 06 20:56:27 2019

answered Jun 21 '19 at 08:12

F. Knorr

3,045
15
22

theres no where for me to write this code. I need to ignore it in the regex. Thanks in advance – Gaurav Bhatnagar Jun 21 '19 at 08:29
@GauravBhatnagar : Can you please provide sample code which shows how you want to modify the log file? – F. Knorr Jun 21 '19 at 08:30

Abhishek · Answer 2 · 2019-06-21T08:38:35.057

0

You can try something like this :

public class Main {
  public static void main(String args[]) {
    String test = "[Wed Mar 06 20:56:27.121877 2019]";
    System.out.println(test.replaceAll("\\.[0-9]+|\\[|\\]", "").substring(test.indexOf(' ')));
  }
}

Output:

Mar 06 20:56:27 2019

edited Jun 21 '19 at 08:38

answered Jun 21 '19 at 08:27

Abhishek

1,558
16
28

Ashwin · Answer 3 · 2019-06-21T09:49:35.637

0

Start the regex from the month, ignore the Day. It would look similar to the below code snippet:

String dateform = "[Wed Mar 06 20:56:27.121877 2019]";
    String regex ="(\\S+ \\d+ \\d+:\\d+:\\d+)";
    Pattern p = Pattern.compile(regex);
    Matcher m = p.matcher(dateform);
    if(m.find()){
       System.out.println(m.group(0));

    }

Output:

Mar 06 20:56:27

edited Jun 21 '19 at 09:49

answered Jun 21 '19 at 08:30

Ashwin

41
5

Ignoring a string within a token regex

3 Answers3