How can I overload char*?

Question

I was asked that in a method class receive a char* and copy that in the member of the class, and if I don´t receive any parameter assign "Sin nombre" to the parameter

void VEHICULO::Set_Nombre(const char* c){
      //No problem here
}

int main(){
      VEHICULO a;
      a.Set_Nombre("FERRARI");//ITS OK
      a.Set_Nombre();         //the class doesnt know that method
}

know how to copy the passed char* or copy "Sin nombre", but when in main I call without a parameter the class doesn´t recognize it, and it should work with the same method, I can´t code the method Set_Nombre(void)

score 1 · Answer 1 · answered Jun 23 '19 at 13:40

1

C++ default arguments.

void VEHICULO::Set_Nombre(const char* c = "Sin Nombre")
{
}

answered Jun 23 '19 at 13:40

Michael Chourdakis

10,345
3
42
78

If I call Set_Nombre(void) it recognizes the default? I'll try it Thanks!!!! – Tobias Piizzi Jun 23 '19 at 13:44
You call it *without* parameters and the default is used. – Michael Chourdakis Jun 23 '19 at 13:48

How can I overload char*?

1 Answers1

Linked