Sort array of dicts in python based on other array

Question

I have an array of dicts, [{'id': 1, 'name': 'one'}, {'id':2, 'name': 'two'}, {'id': 3, 'name': 'three'}] and the array with sorted ids [3, 1, 2]

The expected result is

[{'id': 3, 'name': 'three'}, {'id': 1, 'name': 'one'}, {'id': 2, 'name': 'two'}]

What is the best way to do this?

My code is based on two for:

a = [{'id': 1, 'name': 'one'}, {'id': 2, 'name': 'two'}, {'id': 3, 'name': 'three'}]
b = [3, 1, 2]

res = []

for index in b:
    for player in a:
        if index == player['id']:
            res.append(player)

print(res)

score 3 · Accepted Answer · answered Jun 25 '19 at 13:27

3

sorted(a, key=lambda d: b.index(d['id']))

answered Jun 25 '19 at 13:27

Alex Hall

34,833
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score 2 · Answer 2 · answered Jun 25 '19 at 13:27

2

Try this :

>>> a = [{'id': 1, 'name': 'one'}, {'id':2, 'name': 'two'}, {'id': 3, 'name': 'three'}]
>>> b = [3,1,2]
>>> sorted(a, key= lambda x: l.index(x['id']))
[{'id': 3, 'name': 'three'}, {'id': 1, 'name': 'one'}, {'id': 2, 'name': 'two'}]

answered Jun 25 '19 at 13:27

Arkistarvh Kltzuonstev

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Sort array of dicts in python based on other array

2 Answers2