Random String in Bash Script

Asked Jun 25 '19 at 15:55

Active Jun 25 '19 at 16:02

Viewed 27 times

I am trying to play a random .wav file from the command line. The files are called 1.wav, 2.wav, .... 10.wav

I have created the following .sh script and given it the appropriate execution rights:

#!/bin/sh
rnd=$((1 + RANDOM % 10))
cmd="aplay -D default:CARD=Device ./$rnd.wav"
echo $cmd

and it always returns

aplay -D default:CARD=Device ./1.wav

What am I missing? Thanks for your help!

edited Jun 25 '19 at 16:02

Cyrus

asked Jun 25 '19 at 15:55

ChrisB

2

[Can't replicate](https://repl.it/@kamilcukrowski/SpicySandyUtilities). Works fine. Maybe the shell doesn't support `RANDOM`? Change `/bin/sh` to `/bin/bash` and make sure you run bash. Try `echo $BASH_VERSION` from within the script. – KamilCuk Jun 25 '19 at 15:59
@KamilCuk thanks, `/bin/bash` was the problem! Brilliant! – ChrisB Jun 26 '19 at 11:21

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