I am looking for a solution to know if a specific word or digit is last in the line, followed by nothing , not even space

Question

set vv "abc 123 456 "

regexp {abc[\s][\d]+[\s][\d]+} $vv 
1
regexp {abc[\s][\d]+[\s][\d]+(?! )} $vv 
1

Should return 0, as the line contains extra space at the end or extra characters.

From a list of lines, i am trying to know which lines have space at the end and which do not.

lines can be of any format, for instance, i need to extract line 1 and 3 but not 2 and 4.

1. "abc 123 456"
2. "abc 123 456 abc 999"
3. "xyz 123 999"
4. "xyz 123 999 zzz 222"

Answer 1

You could use a repeating pattern matching a space and digits to make sure that the line ends with digits only:

^abc(?: \d+)+$

Regex demo

Or a bit broader match using word characters \w if the lines can be of any format:

^\w+(?: \w+)+$

Regex demo

Answer 2

Not sure about TCL regex, but I think you have to add an anchor:

abc\s\d+\s\d+$

Answer 3

The regular express would be {^abc.*\d$} -- a digit followed by the end of the string.

% regex {^abc.*\d$} $vv
0

The glob pattern would be {abc*[0-9]}

% string match {abc*[0-9]} $vv
0
% string match {abc*[0-9] } $vv
1

Answer 4

It can be summarized as ending of line ($) proceeding by words(\w).

puts [regexp {\w$} $vv]

Answer 5

If all you need is to find out if a line ends with a space or not, use this for a regex:

\s$