Trying to send random number with post request

Question

I'm trying to send a post request with a random generated number. My script generates the random number fine. My problem is that it's not sending the generated number correctly. It only sends the first part. Which is 100 and not the generated number.

You can see where I've added the variable(number) to the request shown below in the code.

Math.floor((Math.random() * 100) + 1);
var number = [[100,Math.floor((Math.random() * 100) + 1)]]

window.onkeydown = function(event) {
if (event.keyCode === 84) {
console.log('started');
$.post("/draw.php?ing=_index", {
                l: parseInt(number), //<<<< MY ERROR IS HERE!!
                w: ("15"),
                c: ("#0000ff"),
                o: ("100"),
                f: ("1"),
                _: ("false")
            })
console.log(number)
}
};

I've put MY ERROR IS HERE!! where the error may be happening at. So right now it's sending that post request data of l: as [[100]] I would like it to send with the generated number. Making the l: data like [[100,75]] (As a example.)

Neii · Accepted Answer · 2019-06-29T21:56:07.507

0

Instead of parseInt, you can use JSON.stringify to get your array as string:

l: JSON.stringify(number), // => "[[100,75]]"

Edit: Define number inside the function:

window.onkeydown = function(event) {
  var number = [[100,Math.floor((Math.random() * 100) + 1)]];
  ...

edited Jun 29 '19 at 21:56

answered Jun 29 '19 at 21:39

Neii

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2
7

Its only generates the random number once. Than I have to refresh just to make it regenerate a new number. How to make it generate a random number everytime the key is pressed. – Hex Jun 29 '19 at 21:43
Define `number` inside the function (see edited answer). – Neii Jun 29 '19 at 21:49

Trying to send random number with post request

1 Answers1