How do I retrieve matches for every possible pair of numbers in a string?

Question

I need to find a regular expression that retrieves every possible pair of numbers that are together in a string.

I have tried with /\d{2}/g and /[0-9][0-9]/g and it burns the char after it matches it once.

input: "1234567890"

output with the regexp up there: ["12", "34", "56", "78", "90"]

required output: ["12", "23", "34", "45", "56", "67", "78", "89", "90"]

You could use overlapping matches like `(\d)(?=(\d))` and then get group 1 and 2 or `(?=(\d\d))` and then get only group 1. See https://rextester.com/RTWT22863 and https://rextester.com/IQQP46046 — The fourth bird, Jul 02 '19 at 15:32
Hope there would be a way with regex, I would use loops and individual test if I could — CRz, Jul 02 '19 at 15:51

score 0 · Answer 1 · answered Jul 02 '19 at 15:35

0

Like this?

const re = /\d{2}/g
let str = "1234567890"
let arr = str.match(re)
str = str.slice(1)
arr = arr.concat(str.match(re))
console.log(arr.sort((a, b) => a - b))

answered Jul 02 '19 at 15:35

mplungjan

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like that, but only with regex – CRz Jul 02 '19 at 16:09

score 0 · Answer 2 · answered Jul 02 '19 at 16:52

I do not think there is a way to return a character and not consuming it using match. However, you could chain a replace and a match to achieve the expected result.

let input = '1234567890';
let output = input.replace(/\d(?=\d)/g, (m, i) => m + input[i + 1]).match(/\d\d/g);
// ["12", "23", "34", "45", "56", "67", "78", "89", "90"]

How do I retrieve matches for every possible pair of numbers in a string?

2 Answers2