Overloading by return type is not possible. You may use std::variant instead:
#include <variant>
class Base {
public:
virtual std::variant<int, Eigen::VectorXf> sample()=0;
};
class Derived : public Base {
std::variant<int, Eigen::VectorXf> sample() override {return 1;}
};
If one is restricted to C++11, then there are many alternatives.
- Implement and use something like variant: a class that has a enumerator selecting between two active types, and a union to contain these types.
- Use Boost variant.
- std::pair
Implement a hierarchy of classes (a simplification of std::any), and return on the right pointer to object:
class AbstractBase {
public:
virtual ~AbstractBase() = 0;
template <class T>
const T* get() const;
};
template <class T>
class ValueWrapper : public AbstractBase {
public:
ValueWrapper(const T& value) : m_value(value) {}
const T & getValue() const { return m_value; }
private:
T m_value;
};
template <class T>
inline const T * AbstractBase::get() const {
auto child = dynamic_cast<ValueWrapper<T> const*>(this);
return child ? &child->getValue() : nullptr;
}
class Base {
public:
virtual std::unique_ptr<AbstractBase> sample()=0;
};
The question is, why would you need this?