Call asmx mail service GET/POST with python 3

Question

I am consuming a web mail asmx service with python as client. However I do not understand how to upload a file with the same service.

The only information I have from the how to use specifications of the server is the placeholders:

GET /mailservice/mailservice.asmx/SendMailWithAttachment?MailFrom=string&NameFrom=string&ListMailTo=string&Subject=string&Body=string&FileName=string&FileContent=string&FileContent=string&FileType=string HTTP/1.1

and this:

HTTP POST
HTTP/1.1 200 OK
Content-Type: application/x-www-form-urlencoded
Content-Length: length

HTTP GET
HTTP/1.1 200 OK
Content-Type: text/xml; charset=utf-8
Content-Length: length

This is what I have tried

filename = "status.csv"
filecontent = open(os.path.basename(filename), 'r').read()

sendmail_service_with_attachment(HOST, URL, email, subject, content, toemail, fromname, filename, filecontent, 'text/csv')

def sendmail_service_with_attachment(host, url, tomail, mailtitle, mailbody, 
                     mailfrom, namefrom, filename, filecontent, filetype):
    """
    Email Notification by Web Service
    MailFrom=string&NameFrom=string&ListMailTo=string&Subject=string&Body=string&FileName=string&FileContent=string&FileContent=string&FileType=string
    """
    try:
        payload = {
                'MailFrom': mailfrom, 
                'NameFrom': namefrom, 
                'ListMailTo': tomail, 
                'NameTo': '', 
                'Body': mailbody, 
                'FileName':filename, 
                'FileContent': filecontent,
                'FileType':filetype
                }

        data = json.dumps(payload)
        response = requests.post(host + url, data)

        return response

I also tried to send the request as a string as follow:

      request_string = host + url + 'MailFrom=' + mailfrom +\
        '&NameFrom=' + namefrom + '&ListMailTo=' +\
        tomail + '&NameTo=' + "" + '&Subject=' +\
        mailtitle + '&body=' + mailbody +\
        'FileName=' + filename +\
        'FileContent=' + filecontent +\
        'FileType=' +filetype

     response = requests.get(request_string)

I expect the asmx service send the file as attachment Response [200], but I receive a Response [500] for the first one and a Response [414] as response for the last one, which I think is because my request is not well constructed. Based on that information, What could be the way to send the file content of a csv file via get/post to a asmxl webmail service?

score 0 · Answer 1 · answered Jul 03 '19 at 09:41

Some characters in URLs have special meanings (like '/' or '&') so if these appear in your file, they will make it impossible for the webserver to understand your request.

Try encoding the parameters on your URL

import urllib.parse
complete_url = host + url + urllib.parse.encode(payload)

https://stackoverflow.com/a/5607708

I assume that your .csv file is containing text, if it contains binary you may have to base64 encode that data manually before adding it to the URL.

Call asmx mail service GET/POST with python 3

1 Answers1