How to get a java/resources file to InputStream?

Question

I have an excel file in src/main/resources (/resources/files/templates). I want to read it to InputStream. I am not finding the right syntax for this.

String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";

    try {
        InputStream inputStream = new URL("file:///"  + fn).openStream();

Above is not working. I think the path is wrong. How to give correct path for files stored in resources?

What have you tried? Could you show us some code of your attempts? — n247s, Jul 05 '19 at 11:23
Possible duplicate of [Read file from resources folder in Spring Boot](https://stackoverflow.com/questions/44399422/read-file-from-resources-folder-in-spring-boot) — Sergii Zhevzhyk, Jul 05 '19 at 11:34

score 0 · Answer 1 · answered Jul 05 '19 at 11:32

0

This one works for me.

InputStream is = YourClass.class.getClassLoader().getResourceAsStream("relative path to your file starting from resources folder");

answered Jul 05 '19 at 11:32

Mansur

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score 0 · Answer 2 · answered Jul 05 '19 at 11:35

If you are in any method (static or non-static):

String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
InputStream in = Clazz.class.getResourceAsStream(fn);

Where Clazz is the name of the class you are in.

If you are in a non-static method:

String fn = "/resources/files/censusTemplates/SimpleStandardTemplate.xlsm";
InputStream in = getClass().getResourceAsStream(fn);

How to get a java/resources file to InputStream?

2 Answers2