Using ints,strings, and chars to make equation int

Question

I am trying to make something like this work.

string operator = "+";
int randomNumber = 1;
int randomNumber2=2;

if(randomNumber+operator+randomNumber2 == 3)

But can't seem to get it to work, I also tried to do a char with no luck either.

So is it `c#` or `c++` - two vastly different languages (albeit with some common roots). — 500 - Internal Server Error, Jul 07 '19 at 22:22
This is c# that I am using the syntax in. I know they are very similar which is why I did both. So I'm grabbing input from boxes, so I have converted numbers and stuff. — user11295998, Jul 07 '19 at 22:23

score 1 · Answer 1 · answered Jul 07 '19 at 22:34

the example you shared is completely wrong, One suggest for your issue:

  public static int Operator(this string logic, int x, int y)
    {
        switch (logic)
        {
            case "+": return x + y;
            case "-": return x - y;
            // And add your own cases

            default: throw new Exception("invalid logic");
        }
    }

score 1 · Answer 2 · answered Jul 07 '19 at 22:34

1

Simply,

if (operator == '+') return randomNumber + randomNumber2;

With more operators

switch (operator)
{
    case '+': return randomNumber + randomNumber2;
    case '-': return randomNumber - randomNumber2;
    ...
}

answered Jul 07 '19 at 22:34

Kit

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Jonathan Wood · Answer 3 · 2019-07-07T22:45:45.403

0

I posted a class that will parse a full expression on Black Belt Coder. That code simply tokenizes the input text and constructs an infix express, which it then evaluates. It allows you to define your own functions and variables too. Would that work in your case?

Also, may I ask why you want this? I would consider putting it on NuGet if I thought there was any demand.

edited Jul 07 '19 at 22:45

answered Jul 07 '19 at 22:38

Jonathan Wood

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Using ints,strings, and chars to make equation int

3 Answers3