Removing Nan from a list of dataframe in R

Question

I am trying to convert NaN into zeroes. And, the code I am using is as follows

myfiles6 <- lapply(myfiles6, function(x) {x[is.nan(x)] <- 0; x})

but it gives an error as

Error in is.nan(x) : default method not implemented for type 'list'

What could be the solution?

as the error says, you `is.nan` works for vectors, May be you need `lapply(myfiles6, function(dat) {dat[] <- lapply(dat, function(x) replace(x, is.nan(x), 0)); dat})` — akrun, Jul 09 '19 at 14:00
this works but I would be too happy if it can be simplified, I guess it is a nested function. — ambrish dhaka, Jul 09 '19 at 14:11
Perhaps you can use `map(myfiles6, ~ .x %>% mutate_all(~ replace(., is.nan(.), 0)))` from `tidyverse` — akrun, Jul 09 '19 at 14:13

score 0 · Answer 1 · answered Jul 09 '19 at 14:05

0

Try using the following code:

is.nan.data.frame <- function(x)
  do.call(cbind, lapply(x, is.nan))

myfile6[is.nan(myfile6)] <- 0

answered Jul 09 '19 at 14:05

Punkprince17

1 Answers1