Meaning of unsigned char (*pArray[10][10]);

Question

What does the following declaration mean?

unsigned char (*pArray[10][10]);

The braces have no effect in this declaration. Are you sure you reproduced it correctly? — AnT stands with Russia, Apr 17 '11 at 18:33

score 4 · Answer 1 · answered Apr 17 '11 at 18:32

4

Declaration

unsigned char (*pArray[10][10]);

is exactly equivalent to

unsigned char *pArray[10][10];

The parentheses are entirely redundant and have no effect at all. This is a 2D 10x10 array of unsigned char * pointers.

answered Apr 17 '11 at 18:32

4

"entirely redundant and have no effect at all" - isn't that phrasing a bit redundant? :) – thedayturns Apr 17 '11 at 18:45
1

Well, every time I think about redundancy I always come up with such excessive phrasing all the time without a single exception :) – AnT stands with Russia Apr 17 '11 at 18:47
At least AndreyT is not an Oxymoron.haha – Sadique Apr 17 '11 at 18:49
I can weasel my way out of this: in case of `int ((*p))[10]` braces are redundant but do have effect (i.e. the extra pair of braces is redundant, but in general braces matter), while in case or `int ((p))` the braces are both redundant and have no effect :) – AnT stands with Russia Apr 17 '11 at 18:52

score 3 · Accepted Answer · edited May 23 '17 at 12:34

3

cdecl says:

declare pArray as array 10 of array 10 of pointer to unsigned char

Basically what you did was to declare a 2-D Array of pointers.

See this question:

Now try to parse this:

int **(*f)(int**,int**(*)(int **,int **));

[ In your mind of course ]

edited May 23 '17 at 12:34

Community

answered Apr 17 '11 at 18:25

Sadique

That's simple... pointer to function that returns an `int**`, and takes two arguments, an `int**` and a pointer to a function that takes two `int**` as arguments and return another `int**`... Adding a few arrays there would make it a little more interesting... `int *(*p( int** ))[10]`, as one of the function arguments... – David Rodríguez - dribeas Apr 17 '11 at 19:27
2

@David::Hmm.. how about this: `int **(*f)(int**,int**([5])(int **,int **[5]))[5]();` – Sadique Apr 17 '11 at 22:35

score 0 · Answer 3 · edited Aug 13 '12 at 14:37

0

declare pArray as array 10 of array 10 of pointer to unsigned char

edited Aug 13 '12 at 14:37

j0k

answered Apr 17 '11 at 18:26

Nikolai Fetissov

3 Answers3