I am building a website for my own use and was wondering if it is possible to launch a specific android app by clicking a button on the site when it is opened in browser on my phone.
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This involves modifying code of the app. I want to launch any app that is not mine and I don't have source code to. – Krisjanis Lejejs Jul 09 '19 at 16:24
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You can't open any application unless you know the scheme for the application.
To learn more about Deep Links, check this out. https://developer.android.com/training/app-links/deep-linking
This is from Android Documentation.
The way it works is pretty simple. In the Android application you need to apply...
<activity
android:name="com.example.android.GizmosActivity"
android:label="@string/title_gizmos" >
<intent-filter android:label="@string/filter_view_http_gizmos">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<!-- Accepts URIs that begin with "http://www.example.com/gizmos” -->
<data android:scheme="http"
android:host="www.example.com"
android:pathPrefix="/gizmos" />
<!-- note that the leading "/" is required for pathPrefix-->
</intent-filter>
<intent-filter android:label="@string/filter_view_example_gizmos">
<action android:name="android.intent.action.VIEW" />
<category android:name="android.intent.category.DEFAULT" />
<category android:name="android.intent.category.BROWSABLE" />
<!-- Accepts URIs that begin with "example://gizmos” -->
<data android:scheme="example"
android:host="gizmos" />
</intent-filter>
</activity>
For example, the code above will look for the http
and also the scheme for example
So links could be http://www.gizmos.com
OR example://gizmos
. But since you are looking to open any application, this would not be possible unless you know their scheme and path.... which would be pretty unlikely.

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