Remove only time from array of dates Swift

Question

I am getting dates from an api like this:

["2019-07-12 12:43:00", "2019-07-09 12:57:35", "2019-07-09 12:04:33", "2019-07-05 14:32:32", "2019-07-04 17:50:23", "2019-07-02 12:12:30", "2019-07-01 18:09:28"]

but what I want is I want to remove the time from this array of dates to get the dates like this

I want my desired result like this

["2019-07-12", "2019-07-09", "2019-07-09", "2019-07-05", "2019-07-04", "2019-07-02", "2019-07-01"]

The reason why I want because I need to show the events on FSCalendar. How can I do this?

Are that all strings? Do they have a fixed format? Can you just take the first 10 characters? – You surely tried something, don't hesitate to show your attempt! — Martin R, Jul 12 '19 at 11:24
@MartinR....Yes they all are the strings and the format comes same to all dates and I tried this answer https://stackoverflow.com/questions/35392538/remove-time-from-a-date-like-this-2016-02-10-000000 but t showed the fatal error — Wings, Jul 12 '19 at 11:26
if all are strings use [split strings](https://stackoverflow.com/questions/25678373/split-a-string-into-an-array-in-swift) and store the first object into array thats all — Anbu.Karthik, Jul 12 '19 at 11:26
@Anbu.Karthik... I seen that answer but all of them are just splitting a variable of string not array — Wings, Jul 12 '19 at 11:28
@Wings make sure your strings are local time otherwise (if they are UTC time) you would need to parse your dates — Leo Dabus, Jul 13 '19 at 16:11

score 4 · Accepted Answer · answered Jul 12 '19 at 11:35

You can simply use a combination of compactMap(_:) and components(separatedBy:) like,

let arr = ["2019-07-12 12:43:00", "2019-07-09 12:57:35", "2019-07-09 12:04:33", "2019-07-05 14:32:32", "2019-07-04 17:50:23", "2019-07-02 12:12:30", "2019-07-01 18:09:28"]

let result = arr.compactMap({ $0.components(separatedBy: " ").first })

score 2 · Answer 2 · answered Jul 12 '19 at 11:25

2

Please check below code:

    let arr = ["2019-07-12 12:43:00", "2019-07-09 12:57:35", "2019-07-09 12:04:33", "2019-07-05 14:32:32", "2019-07-04 17:50:23", "2019-07-02 12:12:30", "2019-07-01 18:09:28"]

    var arrOnlyDates = [String]()
    for (_,str) in arr.enumerated(){
        let s = str.components(separatedBy: " ")
        arrOnlyDates.append(s[0])
    }
    print(arrOnlyDates)

answered Jul 12 '19 at 11:25

Pratik Patel

1,393
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18

1

Why use `enumerated()` if you only discard the offset? – Martin R Jul 12 '19 at 11:54

score 1 · Answer 3 · answered Jul 12 '19 at 11:34

You can simply get dates array like this:

let dateArray = ["2019-07-12 12:43:00", "2019-07-09 12:57:35", "2019-07-09 12:04:33", "2019-07-05 14:32:32", "2019-07-04 17:50:23", "2019-07-02 12:12:30", "2019-07-01 18:09:28"]

let onlyDatesArray = dateArray.compactMap({ $0.components(separatedBy: " ")[0] })

print("only dates -> \(onlyDatesArray)")

score 1 · Answer 4 · answered Jul 12 '19 at 11:35

let dateStrings = ["2019-07-12 12:43:00", "2019-07-09 12:57:35", "2019-07-09 12:04:33", "2019-07-05 14:32:32", "2019-07-04 17:50:23", "2019-07-02 12:12:30", "2019-07-01 18:09:28"]    
let dateFormatter = DateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
let dates = dateStrings.compactMap { dateFormatter.date(from: $0) }
dateFormatter.dateFormat = "yyyy-MM-dd"
let formatedDateStrings = dates.compactMap { dateFormatter.string(from: $0) }

score 1 · Answer 5 · answered Jul 12 '19 at 14:17

As the date format doesn't change just strip the first 10 characters from each string

let dates = ["2019-07-12 12:43:00", "2019-07-09 12:57:35", "2019-07-09 12:04:33", "2019-07-05 14:32:32", "2019-07-04 17:50:23", "2019-07-02 12:12:30", "2019-07-01 18:09:28"]
let datesWithoutTime = dates.map{ String($0.prefix(10)) }

Remove only time from array of dates Swift

5 Answers5