Array.sort() function isn't returning expected result. Is that how it actualy works, or what?
const arr = [1, 5, 12, 8, 17];
console.log(arr.sort());
Expected result would be: [1, 5, 8, 12, 17] but result I get is: [1, 12, 17, 5, 8]
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4The default comparison function for `.sort()` compares values as *strings*. You have to pass an explicit comparator function if you want to do anything else. – Pointy Jul 12 '19 at 15:22
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Try `arr.sort((a, b) => a - b)`. – slider Jul 12 '19 at 15:23
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1@slider that works! – Asca Fasd Jul 12 '19 at 15:23
1 Answers
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You need to pass a callback to sort array of integers. If you don't pass a callback by default it will sort according to UTF-16 code value units. According to MDN
The
sort()method sorts the elements of an array in place and returns the sorted array. The default sort order is built upon converting the elements into strings, then comparing their sequences of UTF-16 code units values
const arr = [1, 5, 12, 8, 17];
console.log(arr.sort((a,b) => a - b));
Maheer Ali
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