parse string of integer sets with intervals to list

Question

I have "2,5,7-9,12" string.

I want to get [2, 5, 7, 8, 9, 12] list from it.

Is there any built-in function for it in python?

Thanks.

UPD. I suppose, the straight answer is No. Anyway, thanks for your "snippets". Using one, suggested by Sven Marnach.

A duplicate. http://stackoverflow.com/questions/712460/interpreting-number-ranges-in-python — S.Lott, Apr 18 '11 at 17:16

score 15 · Answer 1 · answered Apr 18 '11 at 15:13

15

s = "2,5,7-9,12"
ranges = (x.split("-") for x in s.split(","))
print [i for r in ranges for i in range(int(r[0]), int(r[-1]) + 1)]

prints

[2, 5, 7, 8, 9, 12]

answered Apr 18 '11 at 15:13

Sven Marnach

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Really nice. We even can combine it in one line. – disfated Apr 18 '11 at 15:29

score 5 · Answer 2 · answered Apr 18 '11 at 15:13

s = "2,5,7-9,12"
result = list()

for item in s.split(','):
    if '-' in item:
        x,y = item.split('-')
        result.extend(range(int(x), int(y)+1))
    else:
        result.append(int(item))

print result

Sean Summers · Accepted Answer · 2015-10-20T19:47:03.683

This version handles arbitrary whitespace, overlapping ranges, out-of-order ranges, and negative integers:

from itertools import chain

def group_to_range(group):
  group = ''.join(group.split())
  sign, g = ('-', group[1:]) if group.startswith('-') else ('', group)
  r = g.split('-', 1)
  r[0] = sign + r[0]
  r = sorted(int(__) for __ in r)
  return range(r[0], 1 + r[-1])

def rangeexpand(txt):
  ranges = chain.from_iterable(group_to_range(__) for __ in txt.split(','))
  return sorted(set(ranges))


>>> rangeexpand('-6,-3--1,3-5,7-11,14,15,17-20')
[-6, -3, -2, -1, 3, 4, 5, 7, 8, 9, 10, 11, 14, 15, 17, 18, 19, 20]
>>> rangeexpand('1-4,6,3-2, 11, 8 - 12,5,14-14')
[1, 2, 3, 4, 5, 6, 8, 9, 10, 11, 12, 14]

score 2 · Answer 4 · answered Apr 18 '11 at 15:12

2

Not that I'm aware of, but you can easily make your own:

Create a results list.
Split strings by , and start iterating over the result.
1. If the current string contains a - append a range to the list.
2. If the current string is a number, append it to the list.
3. Else return an error.
Return the list.

answered Apr 18 '11 at 15:12

orlp

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Someone must be in a bad mood to downvote all those correct answers. I'll bring them back to zero :) – Sven Marnach Apr 18 '11 at 15:19

score 2 · Answer 5 · answered Apr 18 '11 at 15:14

I am not aware of any built-in function that would do that. The following isn't particularly elegant, but gets the job done:

s = "2,5,7-9,12"
ret = []
for tok in s.split(","):
  val = map(int, tok.split("-"))
  if len(val) == 1:
    ret += val
  else:
    ret += range(val[0], val[1] + 1)
print ret

One area where this solution may need work is the handling of negative numbers (it is not entirely clear from your question whether negative numbers can appear in the input).

In my case i only have to handle positive int's, although it is good to have universal solution. — disfated, Apr 18 '11 at 15:35

score 2 · Answer 6 · answered Apr 18 '11 at 15:17

I would define function:

def make_range(s):
    out = []
    s = s.split(',')
    for n in s:
        if '-' in n:
            n = n.split('-')
            for i in range(int(n[0]), int(n[1]) + 1):
                out.append(i)
        else:
            out.append(int(n))
    return out

print make_range("2,5,7-9,12")
#output [2, 5, 7, 8, 9, 12]

parse string of integer sets with intervals to list

6 Answers6

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