How replace number to parameter for space

Question

I want to change:

clk = "{:<48}{}".format(".clk", "(clk),")

to

clk = "{:<WIDTH_SPACE}{}".format(".clk", "(clk),")

where

WIDTH_SPACE=48

How can I do it ?

`clk = "{:<{width_space}}{}".format(".clk", "(clk),", width_space=WIDTH_SPACE)` — Abdul Niyas P M, Jul 17 '19 at 07:11
Possible duplicate of [Format string dynamically](https://stackoverflow.com/questions/4302166/format-string-dynamically) — Georgy, Jul 17 '19 at 08:37

score 1 · Answer 1 · answered Jul 17 '19 at 07:14

1

You can specify WIDTH_SPACE in the format:

clk = "{:<{WIDTH_SPACE}}{}".format(".clk", "(clk),", WIDTH_SPACE=WIDTH_SPACE)

answered Jul 17 '19 at 07:14

Carsten

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Just like mine tho – U13-Forward Jul 17 '19 at 07:14

norok2 · Answer 2 · 2019-07-17T07:21:13.930

1

Just use nested curly brackets, e.g:

clk = "{:<{WIDTH_SPACE}}{}".format(".clk", "(clk),", WIDTH_SPACE=48)

or even better use f strings:

WIDTH_SPACE = 48
text = 'clk'
clk = f".{text:<{WIDTH_SPACE - 1}}({text}),"

edited Jul 17 '19 at 07:21

answered Jul 17 '19 at 07:15

norok2

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score 0 · Answer 3 · answered Jul 17 '19 at 07:12

0

Use format with a specifier:

>>> clk = clk = "{:<{width_space}}{}".format(".clk", "(clk),", width_space=WIDTH_SPACE)
>>> clk
'.clk                                            (clk),'
>>>

answered Jul 17 '19 at 07:12

U13-Forward

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How replace number to parameter for space

3 Answers3