Python - How to search a large string with no spaces, to see if a value exists

Question

I have a large string full of byte code so there is no spaces, I am trying to search for a specific part of that code.

For example;

byte_code = 'ergewyegt6t4738t8347tygfhfh47tg4378t58437t485t454gyfofby3gyfg34t5t6435t3465tg3465t4'

The value I am looking for is 'fhfh47tg'.

I have tried the .find String method but did not have much luck. As mentioned before, the string has no spaces.

I'd expect the output to be true once it has found the pattern within the string.

Please include the code you have tried. str.find should work fine, but it returns `-1` if there's no match. If you don't care where in the string your pattern is found, use `in` operator instead. — Håken Lid, Jul 19 '19 at 09:37
@AniketSahrawat: That will return False only if the substring is found at the beginning of the search string (index 0, which is a falsy value). A non-match will return `-1` which is truthy. Instead you could use `print(byte_code.find('fhfh47tg') != -1)` — Håken Lid, Jul 19 '19 at 09:47
Possible duplicate of [Does Python have a string 'contains' substring method?](https://stackoverflow.com/questions/3437059/does-python-have-a-string-contains-substring-method) — ruohola, Jul 19 '19 at 10:05

heemayl · Answer 1 · 2019-07-19T09:45:31.010

5

You can use the in (__contains__) test for substring existence:

if 'fhfh47tg' in byte_code:
    print('Match found')

You can also look at methods like str.find, str.index FWIW.

edited Jul 19 '19 at 09:45

answered Jul 19 '19 at 09:38

heemayl

39,294
7
70
76

In cpython (and I assume most other runtimes), the implementation of `str.__contains__()` is independent of regular string iteration. https://stackoverflow.com/a/18139681/1977847 – Håken Lid Jul 19 '19 at 09:43
1

Always better than regex. – Aniket Sahrawat Jul 19 '19 at 09:44

score 2 · Answer 2 · answered Jul 19 '19 at 09:36

2

Using re.search is one option:

if re.search(r'fhfh47tg', byte_code):
    print("MATCH")
else:
    print("NO MATCH")

answered Jul 19 '19 at 09:36

Tim Biegeleisen

502,043
27
286
360

score 1 · Answer 3 · answered Jul 19 '19 at 09:38

1

I think you can do

if 'fhfh47tg' in byte_code:
    return True

or

return 'fhfh47tg' in byte_code

answered Jul 19 '19 at 09:38

Djaballah Mohammed DJEDID

579
1
4
13

score 0 · Answer 4 · edited Apr 12 '22 at 14:27

0

you can try the following:

byte_code = 'ergewyegt6t4738t8347tygfhfh47tg4378t58437t485t454gyfofby3gyfg34t5t6435t3465tg3465t4'
    
if 'fhfh47tg' in byte_code:
    print("Value is present.")

(you can change the output as per your liking.)

Peace out.

edited Apr 12 '22 at 14:27

Peter Westlake

4,894
1
26
35

answered Jul 19 '19 at 09:44

Parthik B.

472
1
5
15

Python - How to search a large string with no spaces, to see if a value exists

4 Answers4