How to handle the errors in Selenium Webdriver Node Js. NoSuchElementError

Question

When I run the test, sometimes I got the the following error:

"(node:34959) UnhandledPromiseRejectionWarning: NoSuchElementError: no such element: Unable to locate element:..."

And the test stops.

I want the test to going on and not to stop, but write a message into console.

My code now:

var one = await driver.findElement(By.xpath("//td[.='somethig']/following-sibling::td[1]/strong"));
var two = await one.getText();
await fs.appendFileSync("file.txt", two + ",");

How is it possible? Because I don't need this element, for further run. Thanks :)

It is not the same question man... :/ – Zágonyi Krisztián Jul 25 '19 at 07:15 — Zágonyi Krisztián, Jul 25 '19 at 07:15

score 2 · Accepted Answer · answered Jul 23 '19 at 10:08

2

You only just need to wrap the error you need to log to console in try and catch.

let one = '';
let two = '';
try {
    one = await driver.findElement(By.xpath("//td[.='somethig']/following-sibling::td[1]/strong"));
    two = await one.getText();
} catch (error) {
    console.log(error);
}
await fs.appendFileSync("file.txt", two + ",");

answered Jul 23 '19 at 10:08

Tien Duong

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Thank you. It is nearly good. Just I cant take into a function, because I always get "object promise". :/ But it will be a new question. :) – Zágonyi Krisztián Jul 25 '19 at 07:38

How to handle the errors in Selenium Webdriver Node Js. NoSuchElementError

1 Answers1