how to find in java string case incesitive number of word java

Question

skdoakdoakdoakdpoakdpoakdopkapodkoapdkpoakdpoakdpakpdkapdkpaodkpakdpakdpakdpkpdkadpkapdkpaooooooooooooooooooooooooooooooooooooooooooooooooooo dksaodaodddddddddddddddddddddddddddddddddddsdkaopdkpadpaokdakdopakdpakpda dksaopdoapkdpakdpoakdpokdkapodpadpakdpoakdopakdopkpoakdpapdkapdpada kdposaodpadpakdopakdpoakdpokpdkpakdopadkpakdkdkpadkakdpakdp

       String test1 = "java java java. JAVA! ";
       String test2 = "h w !!! ...";
       String word ="java";
       int count = 0;

      String strArray[] = test2.split(" ");

      for(int i=0; i < strArray.length; i++){
            if (word.equals("java")) {
                `enter code here`   
                 count++;
            }            
            System.out.println(strArray[i]);
      }

    System.out.println(count);
    test1.toUpperCase() + test1.toLowerCase().concat;
    count++;
    test1.toLowerCase();
    count++;
    System.out.println(count);

how to return the occurrences in java case insensitive in java i would been trolling the internet but no luck. In JavaScript i would use are but here i am new so please help. So i need to find as above suggested how many times java case insensitive occurs

See if this helps.. https://stackoverflow.com/questions/767759/occurrences-of-substring-in-a-string. Only change "lastIndex = str.indexOf(findStr,lastIndex);" to "lastIndex = str.toLowerCase().indexOf(findStr,lastIndex);" — Immanuel, Jul 25 '19 at 03:57

score 1 · Accepted Answer · answered Jul 25 '19 at 03:56

hopefully this helps

String inputString = "java java java. JAVA!";

        int counter = 0;
        Pattern pattern = Pattern.compile("JAVA");
        Matcher match = pattern.matcher(inputString.toUpperCase());
        while (match.find()) {
            counter++;
        }

        System.out.println(counter);

score 0 · Answer 2 · answered Jul 25 '19 at 04:04

enter code here:
    String regex = "JAVA";
    String input =  "Java java JAVA ss".toUpperCase();
    Pattern p = Pattern.compile(regex);
    Matcher m = p.matcher(input);
    int count = 0;
    List<Integer> index = new ArrayList<>();
    while (m.find()) {
        count++;
        System.out.println("Match number: " + count);
        System.out.println("start: " + m.start());
        System.out.println("end: " + m.end());

        index.add(m.start());
    }
    System.out.println("count: " + count);
    System.out.println("index: " + index.toString());

The first time I use this, I hope it can help you.

score 0 · Answer 3 · answered Jul 25 '19 at 09:44

For good order:

    Pattern pattern = Pattern.compile("java", Pattern.CASE_INSENSITIVE);
    Matcher matcher = pattern.matcher(inputString);
    int count = (int) matcher.results().count();

Or short:

    int count = Pattern.compile("java", Pattern.CASE_INSENSITIVE)
            .matcher(inputString).results().count();

how to find in java string case incesitive number of word java

3 Answers3