java.io.IOException: Stream closed, when trying to access an XML file from JAR

Question

I'm trying to refer to a XML file into my project so i can parse the data from it.

It is being exported as a .jar file which means i can't refer to it using

 BufferedInputStream in = new BufferedInputStream(new FileInputStream("PhillPlugin.xml"));

which works perfectly when i run it from the JDeveloper IDE

So i replace the line above with the following line:

BufferedInputStream in = new BufferedInputStream(Class1.class.getResourceAsStream("Resources/PhillPlugin.xml"));

But when i'm executing the .jar file

java -jar test.jar in terminal

the java.io.IOException: Stream closed is being triggered.

It's mandatory to do it using Streams and not with any Parsing XML libraries

This is where my files are located:

This is how i'm trying to read it:

Based on this post here

Here is the code if you want to try it:


    public static void main(String[] args) throws  Exception {

     /*This is line 21*/   BufferedInputStream in = new BufferedInputStream(Class1.class.getResourceAsStream("Resources/PhillPlugin.xml"));


        StringBuilder sb = new StringBuilder();
        String genurl=null;
        int cp;
        while ((cp = in.read()) != -1) {
            sb.append((char) cp);
            String t = sb.toString();
            if(t.contains("</AttributeValuePair>"))
            {
                String test = sb.toString();
                String test1p[]=test.split("<value>|</value>");
                genurl=test1p[1];
                break;
            }
        }
        System.out.println(genurl);
        sb=new StringBuilder();
        while ((cp = in.read()) != -1) {

            sb.append((char) cp);
            String t = sb.toString();
            if(t.contains("</AttributeValuePair>"))
            {
                String test = sb.toString();
                String test1p[]=test.split("<value>|</value>");
                genurl=test1p[1];
                System.out.println(genurl);
                break;
            }

        }
        in.close();
    }

This is the stacktrace i'm getting from the terminal after the correct reference to the path

Exception in thread "main" java.io.FileNotFoundException: PhillPlugin.xml (No such file or directory)
    at java.io.FileInputStream.open0(Native Method)
    at java.io.FileInputStream.open(FileInputStream.java:195)
    at java.io.FileInputStream.<init>(FileInputStream.java:138)
    at java.io.FileInputStream.<init>(FileInputStream.java:93)
    at client.Class1.main(Class1.java:21)

Do you manage to read some bytes at all ? Also at which line does the error occur ? — Arnaud, Jul 26 '19 at 09:40
no haven't tried reading bytes, it occures on the BufferedInputStream — Phill Alexakis, Jul 26 '19 at 09:41
Just noticed that the "Resource" part of the path doesn't match the name of the actual directory, which is "Resources" . — Arnaud, Jul 26 '19 at 09:43
Whops, thank you i'm going to fix it, but no, it doesn't work — Phill Alexakis, Jul 26 '19 at 09:44

Stephen C · Accepted Answer · 2019-07-26T09:50:31.563

1

Assuming that the JAR file is created from the project in the normal way, the correct resource path for that XML file will be "/PhillPlugin.xml" not "Resource/PhillPlugin.xml".

Assuming that Class1.class is in the default package, and you use Class::getResourceAsStream, the relative path "PhillPlugin.xml" should work as well.

Use jar tvf your.jar to check that the XML file is in the JAR, and what the resource path for the XML file actually is.

edited Jul 26 '19 at 09:50

answered Jul 26 '19 at 09:44

Stephen C

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Right, the `/PhillPlugin.xml` worked, but when i'm running the `.jar` i'm getting the `FileNotFoundException` – Phill Alexakis Jul 26 '19 at 09:47
Nothing in the code you have shown us can throw `FileNotFoundException`. – Stephen C Jul 26 '19 at 09:49
Also my two loops work, i'm getting the expected result, there is a `break` in the first loop – Phill Alexakis Jul 26 '19 at 09:49
1

Ah ... I missed that. – Stephen C Jul 26 '19 at 09:50
correct, but when i execute the `.jar` it's being triggered – Phill Alexakis Jul 26 '19 at 09:50
Maybe you have the path for the JAR file wrong. – Stephen C Jul 26 '19 at 09:51
I'm running `ls` and i can see the `test.jar` file, so i suppose i'm in the right path to run `java -jar test.jar` – Phill Alexakis Jul 26 '19 at 09:52
1

Add the complete stacktrace to the question. – Stephen C Jul 26 '19 at 09:52
i did , line 21 is this one `BufferedInputStream in = new BufferedInputStream(Class1.class.getResourceAsStream("/PhillPlugin.xml"));` – Phill Alexakis Jul 26 '19 at 09:59
That stacktrace clearly shows that main is `new`-ing a `FileInputStream`. The code you showed us doesn't do that. Like I said in my earlier comment . Have you forgotten to recompile? – Stephen C Jul 26 '19 at 09:59
Yes, that's odd, remember that `Class1.class.getResourceAsStream()` returns an `InputStream` , is it being converted to `FileInputStream` from the `BufferedInputStream`'s Constructor? – Phill Alexakis Jul 26 '19 at 10:02
Nope. The stacktrace shows that main line 21 has an explicit `new FileInputStream(...)` expression. Trust me. I fave been programming in Java for > 20 years. – Stephen C Jul 26 '19 at 10:03
OH MY i forgot to re - `Deploy` the `.JAR` file. Works perfectly thank you.I'm sorry i missed that – Phill Alexakis Jul 26 '19 at 10:06

score 1 · Answer 2 · edited Jul 27 '19 at 20:47

1

(Posted on behalf of the question author; copied from the solution they placed in the question).

I forgot to re-deploy he .JAR file after the change. It works perfectly now

edited Jul 27 '19 at 20:47

Makyen

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answered Jul 27 '19 at 19:18

halfer

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java.io.IOException: Stream closed, when trying to access an XML file from JAR

2 Answers2