How can I make my Python vowel counter count all of the vowels at once, rather than individually?

Asked Jul 28 '19 at 12:37

Active Jul 28 '19 at 12:55

Viewed 32 times

I'm rather new to Python. I've coded this vowel counter:

str = "aeiou"
vowels = 0
for i in str:
  if (i=="a" or "e" or "i" or "o" or "u"):
     vowels = vowels+1
print("The number of vowels is:")
print(vowels)

but it's returning this:

The number of vowels is:
1
The number of vowels is:
2
The number of vowels is:
3
The number of vowels is:
4
The number of vowels is:
5

How can I get it to count all of the vowels at once and just provide the total (i.e. 5 in this case)

edited Jul 28 '19 at 12:55

Radosław Cybulski

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asked Jul 28 '19 at 12:37

Emma Wynne

`if i == "a" or i == "e" or i == "i" or i == "o" or i == "u":` OR `if i in ("a", "e", "i", "o", "u"):`OR `if i in "aeiou":` – furas Jul 28 '19 at 12:38
```if i in str.split('')``` should do – LazyCoder Jul 28 '19 at 12:39
probably you have wrong indentions and you use `print()` inside `for`-loop but you should use it after `for`-loop – furas Jul 28 '19 at 12:41
Indentation problem. Keep the print() statement outside of for loop. – fiveelements Jul 28 '19 at 12:41

How can I make my Python vowel counter count all of the vowels at once, rather than individually?

0 Answers0