How to define _tagert="blank" with echo statement getting variables

Question

I am trying to get a link to open to a blank web viewer page using an echo statement that pulls two variables to create the link.

The following shows my last attempt.

echo "<a target="_blank" href=$link>$media</a>";

I'm getting a syntax error but have gone blank as to where it is.

You should [escape qoutes in your string](https://www.php.net/manual/en/language.types.string.php). `echo "{$media}";` — marv255, Jul 28 '19 at 19:53

score -1 · Answer 1 · answered Jul 28 '19 at 19:55

-1

You should escape double quotes. Also, as a rule of thumb, use htmlspecialchars when composing html attributes:

echo sprintf('<a target="_blank" href="%s">%s</a>', htmlspecialchars($link), $media);

answered Jul 28 '19 at 19:55

vbarbarosh

1 Answers1