Are the expressions arr and &arr same for an array of 10 integers?

Question

I came across this problem while taking the online quiz when i tested it in the online ide(Geeks For Geeks) in C language it actually giving the same result but in the test its answer was False.

#include <stdio.h>

int main() {
    int arr[2] = {1,2};
    printf("%d %d",arr,&arr);
    return 0;
}

Output

-1134751264 -1134751264

The pointer value is the same, although the type is different. — Steve Summit, Jul 29 '19 at 01:12
Note that the values of the pointers are _equivalent_, though do not need to be the same binary pattern nor size. Commonly they are. — chux - Reinstate Monica, Jul 29 '19 at 01:21
The compiler you are using is assuming you are wanting the pointer to the array given you haven't referred to an array element. &arr[0] would also give you the same result, but &arr[1] would give you a different result. I hope that helps. — 42LeapsOfFaith, Jul 29 '19 at 01:35

S.S. Anne · Answer 1 · 2019-07-29T01:29:14.843

0

The values of the pointers are the same, but they have different types: a is an int [2] and &a is an int (*)[2].

Other than the type difference, there's only one variation: If you add one to &a, it points to the next array of five ints after a. However, if you add one to a, it points to the next int after *a.

edited Jul 29 '19 at 01:29

answered Jul 29 '19 at 01:14

S.S. Anne

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Are the expressions arr and &arr same for an array of 10 integers?

1 Answers1