Reading Int value of bytes from inputStream

Question

I am trying to read the ASCII value of bytes in the inputstream. I have the following code

 int bd = 0;
 byte[] buffer = new byte[260];
 while (true) {
     try {
          if ((bd = inputStream.read(buffer, 0, buffer.length)) > 0) {
              Log.d("TAG", "Number of bytes from stream" + bd);
           }

In order to read the value of bytes. I tried one of the following method from this SO example read byte value.

String s = new String(buffer,StandardCharsets.US_ASCII);

System.out.println("data from buffer s : " + s);
Result of s:"/9AAAAAAAAAAAAA=="
System.out.println("data from buffer s : " + parseInt(s)); -- error

String s2 = new String(buffer);
System.out.println("data from buffer s2: " + s2);
Result of s2: �@���������������

How can I get the ASCII values which are int ? I tried to convert string into Int using parseInt(s) but I get thrown into NumberFormatException error

you want a byte value as int (in an `int` variable)? you want the int value that corresponds to 4 bytes? ...? maybe some example in terms of input value and expected output could help — user85421, Jul 31 '19 at 13:14
like: *I have, for example, a String `"/A" and want the respective ASCII values `int[] { 47, 65 }` .* ? — user85421, Jul 31 '19 at 13:20
yes I am looking for that. But the conversion leads to `NumberFormatexception error` — cantona_7, Jul 31 '19 at 13:21
then I didn't understand the "*bytes in the inputstream*" part?? nor the base 64 one? you can get each `char` of the String (`toCharArray()` or `charAt()`) which are actually the code of that character and be cast to `int`(`char ch = ...; int ascii = (int) ch;`) — user85421, Jul 31 '19 at 13:26

Hemant Parmar · Accepted Answer · 2019-07-31T13:23:58.623

2

How can I get the byte values which are int ?

Convert int to string first

 int a = 454545454;
        String data = String.valueOf(a);
        try {
            byte[] bytesdata = data.getBytes("UTF-8");
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        }

on your question change

Replace all non-digit with blank: the remaining string contains only digits.

Integer.parseInt(s.replaceAll("[\\D]", ""))

Now for further have look Get ASCII from int

edited Jul 31 '19 at 13:23

answered Jul 31 '19 at 13:03

Hemant Parmar

3,924
7
25
49

I have reframed my question. Will it work similarly ? – cantona_7 Jul 31 '19 at 13:17
No,Now your question is completely different. – Hemant Parmar Jul 31 '19 at 13:19
sorry for the trouble. I misunderstood. Reading ASCII values leads to that error – cantona_7 Jul 31 '19 at 13:22
@cantona_7 its ok, i edit my post, check it and let me know its useful or not. – Hemant Parmar Jul 31 '19 at 13:24

tmc · Answer 2 · 2019-07-31T13:51:35.950

1

what are you trying to do here? print only the number 9 from the given string? if so you can catch the number format exception and handle it.

or are you trying to print that ascii code for the string "/9AAAAAAAAAAAAA=="?

As Carlos said above, if you have each char in the loop, just cast it to an int and you will get the underlying value in memory.

    char b1 = 'f';
    System.out.println("data from buffer s2: " + (int) b1);


    "data from buffer s2: 102"

edited Jul 31 '19 at 13:51

answered Jul 31 '19 at 13:08

tmc

404
1
7
20

yes, I was looking for that exactly !! sorry for misleading – cantona_7 Jul 31 '19 at 13:08
actually this is not an answer, it is a question! @cantona_7 "that exactly what? this ans.. question has two options – user85421 Jul 31 '19 at 13:10
@CarlosHeuberger ofcourse I understand that. I just edited my question and alos the method I tried – cantona_7 Jul 31 '19 at 13:14
sorry @Carlos Heuberger , I did't have enough internet points to allow me to comment on the original qn. – tmc Jul 31 '19 at 13:30

Reading Int value of bytes from inputStream

2 Answers2