grep command to check count of a string in If statement

Asked Jul 31 '19 at 15:00

Active Jul 31 '19 at 15:00

Viewed 375 times

I am not sure what is wrong with this syntax

 if  [[ echo $list | grep -c 'test'  ]] > 0 ; then
   echo "hello"

 fi

this echo $list | grep -c 'test' prints 1 and I tried

 if  [[ echo $list | grep -c 'test' -gt 1 ]] ; then
   echo "hello"

 fi

Nothing worked. What is the right way of doing this?

asked Jul 31 '19 at 15:00

NewUser123

maybe `if echo "$list"| grep -q 'test' ; then do_your_stuff ; fi` will meet your needs. Good luck. – shellter Jul 31 '19 at 15:09
Possible duplicate of [Assign grep count to variable](https://stackoverflow.com/questions/16327355/assign-grep-count-to-variable) – Nellie Danielyan Jul 31 '19 at 15:12

0 Answers0