Why does making an array pointer work better than an array in this situation

Asked Aug 01 '19 at 18:31

Active Aug 01 '19 at 18:34

Viewed 52 times

I have two ways of creating an array of N+1 elements, all filled with zeroes.

long int *a=new long int[N+1]();

vs.

long int a[N+1] = {0};

why does the first approach work better with larger inputs while the second one usually results in segmentation fault?

asked Aug 01 '19 at 18:31

Ryan Marr

2

Funny you should ask this question on StackOverflow. – melpomene Aug 01 '19 at 18:32
1

The second approach creates the array in stack (rather than in heap), and stack size is usually limited by a few megabytes. – HolyBlackCat Aug 01 '19 at 18:34

0 Answers0