How to count item values from dictionary in python using keyword

Question

I have a dictionary in a below format:

folders = {'Master folder': ['Training'], 'Child folder': ['Training videos', 'Training documents', 'Training workouts', 'Training practicals']}

I want to count the values as below is expected,

count_of_masterfolder = 1
count_of_childfolder = 4

So far I did this,

    co_master = folders.items['Master folder']
    co_child = folders.items['Child folder']
    print(co_master, co_child)

Am getting this error:

    co = folders.items['Master folder']
TypeError: 'builtin_function_or_method' object is not subscriptable

What should I do?

That's not how you index a dictionary - just use `folders[key]`. `items` is a function that returns a view object / list of all key-value pairs in the dictionary. — meowgoesthedog, Aug 05 '19 at 15:38
this doesnt returns me my value, as I said in expected section, I need to store each count values in separate variables and print — ilexcel, Aug 05 '19 at 15:41

inof · Answer 1 · 2019-08-05T15:53:09.353

Do you mean you want count_of_masterfolder = 1 etc. as the output of your program, or do you want the count be assigned to variables?

In the former case, you can use something like this:

for key, value in folder.items():
    print ("count of", key, "=", len(value))

In the latter case, the following will work for your particular case:

count_of_masterfolder = len(folder["Master folder"])
count_of_childfolder = len(folder["Child folder"])

Alexandre B. · Answer 2 · 2019-08-05T15:41:50.217

0

You can try dict comprehension:

{k: len(v) for k,v in folders.items()}

Full example:

folders = {'Master folder': ['Training'], 'Child folder': [
    'Training videos', 'Training documents', 'Training workouts', 'Training practicals']}

print({k: len(v) for k,v in folders.items()})
# {'Master folder': 1, 'Child folder': 4}

edited Aug 05 '19 at 15:41

answered Aug 05 '19 at 15:39

Alexandre B.

5,387
2
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correct, but i need to store each item's count into a separate variables. is that possible? – ilexcel Aug 05 '19 at 15:44
It's a bad practise to create variable dynamically since it's hard to understand, debug, maintain and introduce security issues. A dictionary answers your question. You might have a look at [`eval`](https://docs.python.org/3/library/functions.html#eval) or [`exec`](https://docs.python.org/3/library/functions.html#exec). [*Some readings why they are bad practise*](https://stackoverflow.com/questions/1832940/why-is-using-eval-a-bad-practice). – Alexandre B. Aug 05 '19 at 15:49

Jkind9 · Answer 3 · 2019-08-06T07:24:46.723

0

folders = {'Master folder': ['Training'], 'Child folder': ['Training videos', 'Training documents', 'Training workouts', 'Training practicals']}

for key in list(folders.keys()):
  print(key, len(folders[key]))

>>>> Master folder 1
>>>>Child folder 4

EDIT: (to store outputs in list)

''''
mylist = []
for key in list(folders.keys()):
  print(key, len(folders[key]))
  mylist.extend(len(folders[key]))

edited Aug 06 '19 at 07:24

answered Aug 05 '19 at 15:41

Jkind9

742
7
24

correct ! but I need to store each counts in separate variables – ilexcel Aug 05 '19 at 15:43

score 0 · Answer 4 · answered Aug 05 '19 at 15:46

0

Why need complexity, when you can solve it using only len function

count_of_masterfolder = len(folders['Master folder'])
count_of_childfolder = len(folders['Child folder'])

answered Aug 05 '19 at 15:46

Tony Montana

921
18
46

How to count item values from dictionary in python using keyword

4 Answers4