Why wrong in logic bigger than JQuery?

Question

I have error in my code, this code is operator logic in jquert, but it error:

when i put value dipinjam = 2 & tersedia = 10 result is TRUE, why like this?

var dipinjam = this.value;
var tersedia = $("#tersedia").val();
var sisa = tersedia - dipinjam;

if(dipinjam > tersedia){
     alert("Jumlah barang yang dipinjam melebihi barang tersedia");
}else{
     $("#sisa").val(sisa);
}

because "2" > "10" - just check `sisa < 0` - or `+dipinjum > +tersedia` — Jaromanda X, Aug 06 '19 at 10:02

Nemanja G · Accepted Answer · 2019-08-06T10:11:56.910

0

Just put

if(Number(dipinjam) > Number(tersedia)){
     alert("Jumlah barang yang dipinjam melebihi barang tersedia");
}else{
     $("#sisa").val(sisa);
}

You should compare numbers, not strings

edited Aug 06 '19 at 10:11

answered Aug 06 '19 at 10:04

Nemanja G

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OP asks "why like this" - you've given a solution without explanation :p – Jaromanda X Aug 06 '19 at 10:05

Why wrong in logic bigger than JQuery?

1 Answers1