Java regular expression to validate email address that end with .services

Question

The regular expression to validate email address using java.util.regex.Matcher is failing. It throws invalid email address or false.

How would i modify the pattern to allow email address that ends with .services

import java.util.regex.Matcher;
import java.util.regex.Pattern;

String emailAddress = myemail@something.services;

public static Pattern EMAIL_PATTERN = Pattern.compile(
    "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$");

Matcher matcher = ADDR_PATTERN.matcher(emailAddress);



import java.util.regex.Matcher;
import java.util.regex.Pattern;

String emailAddress = myemail@something.services;

public static Pattern EMAIL_PATTERN = Pattern.compile(
    "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$");

Matcher matcher = ADDR_PATTERN.matcher(emailAddress);

score 3 · Answer 1 · edited Jun 09 '20 at 06:32

3

Rather than using regex, you should use the "built-in" javax.mail.internet.InternetAddress format validator. Regex becomes more complex as you add additional rules, whereas a basic validation and then a strict validation for the suffix is human-readable.

public static boolean isValidEmailAddress(String email) {
    try {
        InternetAddress emailAddr = new InternetAddress(email);
        emailAddr.validate(); //validates email format

        return true;
    } catch (AddressException ex) {
        return false;
    }
}

edited Jun 09 '20 at 06:32

Vishwa Ratna

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answered Aug 08 '19 at 19:51

Compass

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It is nice way, but it may be a domain name that ends with services – taha Aug 08 '19 at 19:54
it only works for .services.. meaning it is stopped working for other emails like gmail, yahoo – skrk Aug 09 '19 at 19:27
@skrk Well, that is what you asked for, a pattern that allows ".services". If you want to allow gmail.com, yahoo.com, and so on, you wouldn't even need to check the suffix. The answer has been updated. – Compass Aug 09 '19 at 19:38

taha · Answer 2 · 2019-08-08T19:51:18.007

0

^[A-Z0-9._%+-]+@[A-Z0-9.-]+\.services$

Pattern pattern = Pattern.compile("^[A-Z0-9._%+-]+@[A-Z0-9.-]+\\.services$", Pattern.CASE_INSENSITIVE);
    Matcher matcher = pattern.matcher("myemail@something.services");
    System.out.println("result: "+matcher.find());

base on Java regex email

edited Aug 08 '19 at 19:51

answered Aug 08 '19 at 19:45

taha

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not really working.. meaning it stopped working for other emails like gmail, yahoo – skrk Aug 09 '19 at 19:27
there is no exception or error thrown it return false for other emails gmail, yahoo, I want the regression that validate all the valid email address one of them is .services – skrk Aug 09 '19 at 19:56
you are right , I found regex for email in this website http://emailregex.com , (?:[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*|"(?:[\x01-\x08\x0b\x0c\x0e-\x1f\x21\x23-\x5b\x5d-\x7f]|\\[\x01-\x09\x0b\x0c\x0e-\x7f])*")@(?:(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0-9])?|\[(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?|[a-z0-9-]*[a-z0-9]:(?:[\x01-\x08\x0b\x0c\x0e-\x1f\x21-\x5a\x53-\x7f]|\\[\x01-\x09\x0b\x0c\x0e-\x7f])+)\]) – taha Aug 09 '19 at 20:53

Java regular expression to validate email address that end with .services

2 Answers2