FileNotFoundException in spring boot jar but the file is present

Question

I am getting FileNotFoundException while the file is clearly present in the jar. why is it so?

java.io.FileNotFoundException: file:/Users/serviceuser/project/coolApp/target/coolApp-1.0-SNAPSHOT.jar!/BOOT-INF/classes!/ssl_certs/mysslstore.jks (No such file or directory)
    at java.base/java.io.FileInputStream.open0(Native Method) ~[na:na]
    at java.base/java.io.FileInputStream.open(FileInputStream.java:219) ~[na:na]
    at java.base/java.io.FileInputStream.<init>(FileInputStream.java:157) ~[na:na]
    at java.base/java.io.FileInputStream.<init>(FileInputStream.java:112) ~[na:na]

However, I see the files packaged in jar.

jar -tf coolApp-1.0-SNAPSHOT.jar | grep ssl

EDIT I load the file as following

new FileInputStream(CoolApp.class.getClassLoader().getResource("ssl_certs/mysslstore.jks").getFile())

The files inside the jar are not part of the traditional file path directory structure. You need to get the resource as a stream. — Compass, Aug 12 '19 at 18:21
@LovaChittumuri it is not certification issue. it is FileNotFoundException — brain storm, Aug 12 '19 at 18:28
Does this answer? https://stackoverflow.com/questions/3803326/this-getclass-getclassloader-getresource-and-nullpointerexception — Lalit Agarwal, Aug 12 '19 at 18:32
@LalitAgarwal nope. I tried what is suggested there and it did not work either — brain storm, Aug 12 '19 at 18:41
Look at davidxxx's answer... it needs to be loaded as a stream when in a jar — RobOhRob, Aug 12 '19 at 19:47

davidxxx · Accepted Answer · 2019-08-17T07:35:52.547

Here :

new FileInputStream(CoolApp.class.getClassLoader().getResource("ssl_certs/mysslstore.jks").getFile());

getFile() is invoked on a URL included in a jar.
As a result, it provides a particular File object since that is not a File directly accessible in the filesystem.

And the URL javadoc confirms that (emphasis is mine) :

Class URL represents a Uniform Resource Locator, a pointer to a "resource" on the World Wide Web. A resource can be something as simple as a file or a directory, or it can be a reference to a more complicated object, such as a query to a database or to a search engine.

So the FileInputStream(File) constructor cannot necessarily be able to open that "special" file :

A FileInputStream obtains input bytes from a file in a file system. What files are available depends on the host environment.

You can compare what you try to do with the following :

new FileInputStream("/Users/serviceuser/project/coolApp/target/coolApp-1.0-SNAPSHOT.jar!/BOOT-INF/classes!/ssl_certs/mysslstore.jks")

As you guessed, the file included in the jar(mysslstore.jks) could not be resolved by the OS filesystem.

Instead of, use getResourceAsStream() that returns an input stream. That input stream refers to the bytes sequence represented by the resource. In this way, the client code doesn't depend any longer on the way which the resource is stored.

InputStream is = CoolApp.class.getClassLoader().getResourceAsStream("ssl_certs/mysslstore.jks"));

`getResourceAsStream()` is the key and it has been forgot so many times for people. — LHCHIN, Aug 13 '19 at 01:25
There is no constructor for new FileInputStream() that takes InputStream. There is no need to wrap `.getResourceAsStream` with FileInputStream. just `CoolApp.class.getClassLoader().getResourceAsStream("ssl_certs/mysslstore.jks")` is sufficient — brain storm, Aug 15 '19 at 17:31
@brain storm In fact it would make no sense at all :) Thanks I fixed the last line. — davidxxx, Aug 17 '19 at 07:36
In this case, CoolApp would be the name of the main class of the Spring project...right? — José Ripoll, Nov 11 '19 at 21:01

score 0 · Answer 2 · answered Apr 22 '20 at 07:03

I was facing the same issue in spring boot and I have tried many things like bellow but nun of them is working. thease all are working locally but  It is giving FileNotFoundException in dev environmnet because when we build a JAR, the resources get placed into the root directory of the packaged artifacts and our downloaded files I placed inside resource folder. 

Method 1: Working solution for jars
InputStream stram=getClass().getClassLoader().getResourceAsStream(File.separator+"database.properties");
URL url = getClass().getClassLoader().getResource(File.separator+"database.properties");

Only thing which worked is ResourceLoader. Need to Autowire it:
    @Autowired
    ResourceLoader resourceLoader;

        Resource resource = resourceLoader.getResource("classpath:" + File.separatorChar + NPIConstants.VAR_FOLDER
                + File.separatorChar + NPIConstants.TPSPIDsBUCKET_FILENAME);
        InputStreamResource isResource = new InputStreamResource(resource.getInputStream());

Method 1: Not Working solution for jars
ClassLoader loader = Thread.currentThread().getContextClassLoader();
InputStream is = loader.getResourceAsStream("database.properties");
System.out.println(is.available());

Method 2:  Not Working solution for jars
Resource resource = new ClassPathResource("database.properties");
InputStream input = resource.getInputStream();

Method 3: Not Working solution for jars
File file = new File("resources/database.properties");
String absolutePath = file.getAbsolutePath();

Method 4: Not Working solution for jars
File file = new File(getClass().getClassLoader().getResource("database.properties").getFile());

Method 5: Not Working solution for jars
ClassLoader classLoader = getClass().getClassLoader();
classLoader.getResource("database.properties");
String path  = classLoader.getResource("database.properties").getPath();

No, resource loader doesn't work for jars either. Also please fix the formatting if possible. — BabyishTank, Mar 11 '22 at 05:44

score -2 · Answer 3 · answered Aug 12 '19 at 18:25

-2

Files like this need to be in the resources directory.

answered Aug 12 '19 at 18:25

Daisy Day

652
7
19

in sourcecode, it is in resources. what I show above is the jar contents. – brain storm Aug 12 '19 at 18:26

FileNotFoundException in spring boot jar but the file is present

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