Can the following be done without loops?
B = np.array([[0, 1, 2, 3],[1, 0, 3, 5],[2, 3, 0, 6],[3, 5, 6, 0]])
mylist = [0, 1, 0, 2, 3, 0] #note the repeats
BigB = np.zeros((len(mylist),len(mylist)),np.int64)
for i,row in enumerate(mylist):
for j,col in enumerate(mylist):
BigB[i,j] = B[row,col]
Output
B
Out[100]:
array([[0, 1, 2],
[1, 2, 3],
[2, 3, 4]])
BigB
Out[101]:
array([[0, 1, 0, 2, 3, 0],
[1, 0, 1, 3, 5, 1],
[0, 1, 0, 2, 3, 0],
[2, 3, 2, 0, 6, 2],
[3, 5, 3, 6, 0, 3],
[0, 1, 0, 2, 3, 0]])
If there were no repeats, I could use direct indexing as in this answer
