How to translate ruby regex to javascript regex?

Question

Im using validates_format_of method to check a input text Javascript cant read this regex. How or where I can change this regex to be as original:

(?<=^|,|\b)[1-7](?=$|,|\b)

Thanks

UPDATE: the input text must be one o more digits separated by comma, ex: 1|1,2|1,2,3

The regex seems to be valid for JavaScript either. Could you provide an example of which text is supposed to be valid, and which is not? — Sergey Mell, Aug 13 '19 at 22:04
The `/\b[1-7]\b/` should do, because `\b` is more generic than `,` and `^`/`$`. — Wiktor Stribiżew, Aug 13 '19 at 22:07
`\b` covers all cases of `^` or `,` behind and `$` or `,` ahead. So, use `/\b[1-7]\b/` However, it is equivalent to this as well `(?:^|,|\b)[1-7](?=$|,|\b)` which is _verbose_ and overstated in the form of `^$` and `,` — , Aug 14 '19 at 01:20
Positive lookbehind is not supported in Mozila and some other browsers too, so you need that to change to normal regex — Code Maniac, Aug 14 '19 at 01:41
the text must be one o more digits separated by comma, ex: 1|1,2|1,2,3 — Edgar Lugo, Aug 14 '19 at 13:28
Ok, try `/(?:^|,)[1-7](?:,|$)/`, why use `\b`? If you are checking against a string, why use lookarounds? — Wiktor Stribiżew, Aug 17 '19 at 22:52

score 0 · Accepted Answer · answered Aug 14 '19 at 11:00

0

As @wiktor said you should use

\b[1-7]\b

As \b only asserts positions, you don't need to worry about matching more than [1-7].

@Code Maniac correctly stated that look behind is not supported in Mozilla and many others, so about it. see

answered Aug 14 '19 at 11:00

YOGO

1 Answers1