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i was trying to integrate rasa to google assistant: https://blog.rasa.com/going-beyond-hey-google-building-a-rasa-powered-google-assistant/

Then after rasa train, I get this error

(voice_bot) arjun@arjun-Lenovo-ideapad:~/Desktop/rasa_google$ rasa train
/home/arjun/enviro/voice_bot/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py:526: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint8 = np.dtype([("qint8", np.int8, 1)])
/home/arjun/enviro/voice_bot/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py:527: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint8 = np.dtype([("quint8", np.uint8, 1)])
/home/arjun/enviro/voice_bot/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py:528: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint16 = np.dtype([("qint16", np.int16, 1)])
/home/arjun/enviro/voice_bot/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py:529: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_quint16 = np.dtype([("quint16", np.uint16, 1)])
/home/arjun/enviro/voice_bot/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py:530: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  _np_qint32 = np.dtype([("qint32", np.int32, 1)])
/home/arjun/enviro/voice_bot/lib/python3.6/site-packages/tensorflow/python/framework/dtypes.py:535: FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'.
  np_resource = np.dtype([("resource", np.ubyte, 1)])
The path 'config.yml' does not exist. Please make sure to use the default location ('config.yml') or specify it with '--config'.

These are my versions:

  • rasa (1.1.8)
  • rasa-core (0.14.5)
  • rasa-core-sdk (0.14.0)
  • rasa-nlu (0.15.1)
  • rasa-sdk (1.1.1)
  • rasa-x (0.20.0)
Alex Bravo
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Arjun Bharadwaj
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  • What's your question? – David Buck Aug 14 '19 at 09:01
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    Is config.yml in the same directory as your executable? If it is in a separate cfg directory, or if you are running my_script from another directory, you may have to say "my_script.py \configs\config.yml" ... you can also use os.chdir(dir_of_config.yml). – aschultz Aug 14 '19 at 09:05
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    @aschultz thank you... i had my config.yml in other directory.. i changed it to my exectable...now its working – Arjun Bharadwaj Aug 14 '19 at 13:41
  • how did you change dir as executable ? – HWJ Nov 20 '19 at 04:50

2 Answers2

1

You just need to run

rasa init

This will take care of setting up your working directory

Sully
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0

The problem is, the current working directory hasn't been selected. Use cd to select the working environment. For example: cd C:\Users\Jinu Augustine\Documents\rasabot. Try rasa train nlu after this, it should work.

Tim Stack
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Jinu Augustine
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