Python: Iterating through a dictionary gives me "int object not iterable"

Question

Here's my function:

def printSubnetCountList(countList):
    print type(countList)
    for k, v in countList:
        if value:
            print "Subnet %d: %d" % key, value

Here's the output when the function is called with the dictionary passed to it:

<type 'dict'>
Traceback (most recent call last):
  File "compareScans.py", line 81, in <module>
    printSubnetCountList(subnetCountOld)
  File "compareScans.py", line 70, in printSubnetCountList
    for k, v in countList:
TypeError: 'int' object is not iterable

Any ideas?

You may want to consider adding type hints to your code for better readability (https://www.python.org/dev/peps/pep-0484/) — Thomas Fritz, Feb 28 '21 at 18:16

score 53 · Answer 1 · edited May 31 '20 at 17:00

53

Try this

for k in countList:
    v = countList[k]

Or this

for k, v in countList.items():

Read this, please: Mapping Types — dict — Python documentation

edited May 31 '20 at 17:00

wjandrea

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answered Apr 21 '11 at 23:01

S.Lott

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score 20 · Answer 2 · answered Apr 21 '11 at 23:06

20

The for k, v syntax is a short form of the tuple unpacking notation, and could be written as for (k, v). This means that every element of the iterated collection is expected to be a sequence consisting of exactly two elements. But iteration on dictionaries yields only keys, not values.

The solution is it use either dict.items() or dict.iteritems() (lazy variant), which return sequence of key-value tuples.

answered Apr 21 '11 at 23:06

Adam Byrtek

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`iteritems()` works in **Python2**, but not in **Python3** where its equivalent is `items()` [SO related question](https://stackoverflow.com/questions/30418481/error-dict-object-has-no-attribute-iteritems/30418498) – datapug Feb 03 '19 at 11:30

score 2 · Answer 3 · answered Apr 21 '11 at 23:03

2

You can't iterate a dict like this. See example:

def printSubnetCountList(countList):
    print type(countList)
    for k in countList:
        if countList[k]:
            print "Subnet %d: %d" % k, countList[k]

answered Apr 21 '11 at 23:03

sinan

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Python: Iterating through a dictionary gives me "int object not iterable"

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