How does the global variable behave inside function(Python)

Question

Case 1

A = '213'
def wow():
    print(A)
wow()
Output: '213'

Case 2

A = '213'
def wow():
    print(A)
    A = 12
wow()
Output: UnboundLocalError: local variable 'A' referenced before assignment

I'd thought that the output in the case 2 would be identical to the case 1, since A is a global variable and I called "print(A)" before reassigning value to A within the function. So my question is, why in the case 1 calling A is perfectly fine, but case 2 throws error?

score 1 · Answer 1 · answered Aug 15 '19 at 11:12

1

Because you are modifying it, so you would need global:

A = '213'
def wow():
    global A
    print(A)
    A = 12
wow()

global allows you to modify it too.

answered Aug 15 '19 at 11:12

U13-Forward

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@Tomerikoo Oh yeah didn't see that, should i delete this – U13-Forward Aug 15 '19 at 11:14

How does the global variable behave inside function(Python)

1 Answers1